(2x + 3)y' = y + (2x + 3)/2; when x = –1,y = 0
Chapter11: Graphs
Section11.1: Use The Rectangular Coordinate System
Problem 11.7TI: Plot each point: (4,-3) (4,3) (4,3) (-4,3)
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solve differential eqn
Transcribed Image Text:(2х + 3)у' %3D у+ (2х + 3)1/2;B when x —D
—1,у %3D 0
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