2s2+3s-4 1. F(s) = (s-2)(s2+2s+2) 1 2. F(s)= s(s2+1)
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- An object's position is given by r(t) = [a + ßt] î+ [y+ot²] 3 where • d = 2.86 m B 3.5 m/s • Ύ 3.15 m • σ = -4.1 m/s² t = 7.2 s = What is its speed v at t = 7.2 s?3.31 m cannot be the answer?11:44 Q < SEARCH & ASK √x MATH SOLVER nc+) = -4.9+²2² +12+ + 45 ↑ ↑ int acceleration velocity AA Speed of rock before hits the ground √²=√12²+ 269.81-45) Fi Transcribed Image Text: h(+) = -4.9+²2² +12€ +45 ↑ ↑ int acceleration velocity tait Speed of rock before hits the ground ✓=√√√12²+2 (98) -45) F 2 Calif bartleby.com Ć
- x+2 If y = what is the value of y when x = 5i? 6-7 61 13 61; 40 61 13 + 0i 40 61 40 61 13 61How do you find instantaneous velocity? Delta X = 30m Vav=0.6 m/s t=10.0sA rodeo horse is running around a corral at a speed of 300 ft/s. Let x(t) be the distance of the horse from the third barrel and y(t) his distance from the fourth. (see figure; note that the distance between barrels is 900 řt). At what rate is the horse's distance from the fourth barrel changing at the instant when he is 200 ft from the third? 2 1 3 4
- Bob has just finished climbing a sheer cliff above a level beach and wants to figure out how high he climbed. All he has to use is a baseball, a stopwatch, and a friend on the ground below with a long measuring tape. Bob is a pitcher and knows that the fastest he can throw the ball is about vo = 33.7 m/s. Bob starts the stopwatch as he throws the ball, with no way to measure the ball's initial trajectory, and watches carefully. The ball rises and then falls, and after t₁ = 0.710 s the ball is once again level with Bob. Bob cannot see well enough to time when the ball hits the ground. Bob's friend then measures that the ball hit the ground x = 123 m from the base of the cliff. How high above the beach was the ball when it was thrown? initial height: X 1₁ mFind the magnitudes of velocities v VA and v VB + y A XX V tot 0 VB in the figure below, where, 0 = 22.5⁰ and Vtot = 7.28 m/s. 23.0% 26.5° VA Vtot = VA + VB VB XFind the components of tot along the x and y axes in the figure below, where 8 = 21.0° and tot Vtot, x V tot, y = = + Vtot = VA + VB УА VB A Vtot 26.5° 23.0% VA X = 7.60 m/s.