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The system of equations is now: (2*) -m1g cos 0+T=m1a2 (4°) Зт1д — Т — Зтјаз = 9.80 meter/second?, 0 = 60°, and is the unknown being solved for. a2

The system of equations is now: (2*) -m1g cos 0+T=m1a2 (4°) Зт1д — Т — Зтјаз = 9.80 meter/second?, 0 = 60°, and is the unknown being solved for. a2

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The two equations must be solved in order to determine a2. I get the result, a2 = 8.6 m/s^2, which is incorrect. I don't know where I'm going wrong.

The system of equations is now: (2*) -m1g cos 0 +T=m¡a2 (4°) Зт1д — Т- Зтјаз where g = 9.80 meter /second?, 0 = 60°, and az is the unknown being solved for.
Transcribed Image Text:The system of equations is now: (2*) -m1g cos 0 +T=m¡a2 (4°) Зт1д — Т- Зтјаз where g = 9.80 meter /second?, 0 = 60°, and az is the unknown being solved for.
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