2s + 16 s² + 4s + 13
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
find the inverse Laplace transform of the given
function. Correct answer for 13 is 2e^(-2t) cos(3t) + 4e^(-2t) sint(3t)
![Certainly! Here is the transcription of the mathematical expression:
---
**13.**
\[
\frac{\frac{2s + 16}{s^2 + 4s + 13}}{6}
\]
---
This notation represents a complex fraction. The main fraction has a numerator and a denominator, where the numerator itself is another fraction. The numerator is \((2s + 16)\) divided by \((s^2 + 4s + 13)\), and this entire expression is divided by 6.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb4f94f1b-b461-4628-ade7-08bc846003b3%2F30f104eb-a4fa-4b3a-9b66-04bba3a8611e%2Fb4qdiq_processed.png&w=3840&q=75)
Transcribed Image Text:Certainly! Here is the transcription of the mathematical expression:
---
**13.**
\[
\frac{\frac{2s + 16}{s^2 + 4s + 13}}{6}
\]
---
This notation represents a complex fraction. The main fraction has a numerator and a denominator, where the numerator itself is another fraction. The numerator is \((2s + 16)\) divided by \((s^2 + 4s + 13)\), and this entire expression is divided by 6.
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