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2K (s)+2 H2O (l) ---> 2 KOH (s)+H2 (g) Molar masses for all compounds in the equation:  K: 39.10 g/mol H2O: 18.02 g/mol KOH: 56.11 g/mol H2: 2.02 g/mol   How many liters of H2 are created from the reaction of 20.0 g potassium (K) with an excess of water? example steps are attached.

2K (s)+2 H2O (l) ---> 2 KOH (s)+H2 (g) Molar masses for all compounds in the equation:  K: 39.10 g/mol H2O: 18.02 g/mol KOH: 56.11 g/mol H2: 2.02 g/mol   How many liters of H2 are created from the reaction of 20.0 g potassium (K) with an excess of water? example steps are attached.

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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2K (s)+2 H2O (l) ---> 2 KOH (s)+H2 (g)

Molar masses for all compounds in the equation: 

K: 39.10 g/mol

H2O: 18.02 g/mol

KOH: 56.11 g/mol

H2: 2.02 g/mol

 

How many liters of H2 are created from the reaction of 20.0 g potassium (K) with an excess of water?

example steps are attached.

Chemistry Vocabulary WORD WALL 12 mass-volume stoichiometry 0₂ (3) +2.50₂ 0.0011 mol 751 moles 0.0625 mol DAL 3 2 CaSO4(s) 1. Convert mass of the given cřente, in moles cº the given chemical using the molar mass of the piven chemical. 2. Convert moles of the given chemical to moles, al the desired chemical using mole ratio. Ünvert role of the desired chemical to volume H How much oxygen (O₂) is required to react completely with 3.5 g CaO? Coo molar mass: 56.08 g/mol cao một 3.5 g Ca x 0.060 mal C-Jx 15 1 mol cag 56.08 g CaQ 1 mol 0 2 md (20) = MEN 0.063 mol (₂0) -0.031 mol 0 -0.70 LO
Transcribed Image Text:Chemistry Vocabulary WORD WALL 12 mass-volume stoichiometry 0₂ (3) +2.50₂ 0.0011 mol 751 moles 0.0625 mol DAL 3 2 CaSO4(s) 1. Convert mass of the given cřente, in moles cº the given chemical using the molar mass of the piven chemical. 2. Convert moles of the given chemical to moles, al the desired chemical using mole ratio. Ünvert role of the desired chemical to volume H How much oxygen (O₂) is required to react completely with 3.5 g CaO? Coo molar mass: 56.08 g/mol cao một 3.5 g Ca x 0.060 mal C-Jx 15 1 mol cag 56.08 g CaQ 1 mol 0 2 md (20) = MEN 0.063 mol (₂0) -0.031 mol 0 -0.70 LO
Chemistry Vocabulary WORD WALL mass-volume stoichiometry + 2 50₂ (8) DA + 07 1701 1. Comment mass of the givendentes formales ol the given chemical using the molar mass of the cendental 7. Convert moles of the given chemical to moles of dve desired chemies using mole ratin Comert moles of the desired chemical to volume of the desired chemical using the molar volume demia| 2 CaSO4 (5) A mill Imdl U. DIRE 2 mal LNO How much oxygen (0,) is required to react completely with 3.5 g CaO? Cnt molov mass: 55,00 g/mol 0 22.4L0, 1 mol 0, 0. 3. 2 -0.70 LO
Transcribed Image Text:Chemistry Vocabulary WORD WALL mass-volume stoichiometry + 2 50₂ (8) DA + 07 1701 1. Comment mass of the givendentes formales ol the given chemical using the molar mass of the cendental 7. Convert moles of the given chemical to moles of dve desired chemies using mole ratin Comert moles of the desired chemical to volume of the desired chemical using the molar volume demia| 2 CaSO4 (5) A mill Imdl U. DIRE 2 mal LNO How much oxygen (0,) is required to react completely with 3.5 g CaO? Cnt molov mass: 55,00 g/mol 0 22.4L0, 1 mol 0, 0. 3. 2 -0.70 LO
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