2a. Provide a divide-and-conquer algorithm that will determine the maximum sum possible for a subarray of a given array. The array only contains the values 1, -1 and -2. [Adapted from IOA, Ch. 4] Example input: 1 -2 1 1 1 1 -1 1 1
2a. Provide a divide-and-conquer algorithm that will determine the maximum sum possible for a subarray of a given array. The array only contains the values 1, -1 and -2. [Adapted from IOA, Ch. 4] Example input: 1 -2 1 1 1 1 -1 1 1
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
2a. Provide a divide-and-conquer algorithm that will determine the maximum sum possible for a subarray of a given array. The array only contains the values 1, -1 and -2. [Adapted from IOA, Ch. 4]
Example input:
1 -2 1 1 1 1 -1 1 1
Expert Solution
Source Code
def maxSum(arr, l, m, h):
sum_el = 0
left_sum = -10000
for i in range(m, l-1, -1):
sum_el = sum_el + arr[i]
if (sum_el > left_sum):
left_sum = sum_el
sum_el = 0
right_sum = -1000
for i in range(m + 1, h + 1):
sum_el = sum_el + arr[i]
if (sum_el > right_sum):
right_sum = sum_el
return max(left_sum + right_sum, left_sum, right_sum)
def maxSumSubArray(arr, l, h):
if (l == h):
return arr[l]
m = (l + h) // 2
return max(maxSumSubArray(arr, l, m),
maxSumSubArray(arr, m+1, h),
maxSum(arr, l, m, h))
arr = [1,-2,1,1,1,1,-1,1,1]
n = len(arr)
max_sum = maxSumSubArray(arr, 0, n-1)
print("Maximum consecutive sum is ", max_sum)
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