2a. Provide a divide-and-conquer algorithm that will determine the maximum sum possible for a subarray of a given array. The array only contains the values 1, -1 and -2. [Adapted from IOA, Ch. 4] Example input: 1 -2 1 1 1 1 -1 1 1

Database System Concepts
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ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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2a. Provide a divide-and-conquer algorithm that will determine the maximum sum possible for a subarray of a given array. The array only contains the values 1, -1 and -2. [Adapted from IOA, Ch. 4] Example input: 1 -2 1 1 1 1 -1 1 1
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def maxSum(arr, l, m, h):

 sum_el = 0
 left_sum = -10000

 for i in range(m, l-1, -1):
  sum_el = sum_el + arr[i]

  if (sum_el > left_sum):
   left_sum = sum_el

 sum_el = 0
 right_sum = -1000
 for i in range(m + 1, h + 1):
  sum_el = sum_el + arr[i]

  if (sum_el > right_sum):
   right_sum = sum_el

 return max(left_sum + right_sum, left_sum, right_sum)


def maxSumSubArray(arr, l, h):

 if (l == h):
  return arr[l]

 m = (l + h) // 2

 return max(maxSumSubArray(arr, l, m),
   maxSumSubArray(arr, m+1, h),
   maxSum(arr, l, m, h))


arr = [1,-2,1,1,1,1,-1,1,1]
n = len(arr)

max_sum = maxSumSubArray(arr, 0, n-1)
print("Maximum consecutive sum is ", max_sum)

 

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