2/9 To satisfy design limitations it is necessary to deter-mine the cffect of the 2 kN tension in the cable on theshear, tension, and bending of the fixed I-beam. Forthis purpose replace this force by its equivalent of twoforces at A, F, parallel and F, perpendicular to thebeam. Determine F, and F.Ans. F, = 1.286 kN, F, = 1.532 kN20°2 kN30Problem 2/9

Answered: Image /qna-images/answer/5637d29f-4c00-4039-9984-8d161fc5f11f.jpg

Answered: 2/9 To satisfy design limitations it is…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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1. To satisfy design limitations it is necessary to determine the effect of the 4.5 kN tension in the cable on the truss. For this purpose replace this force by its equivalent of two forces at A, F: parallel and Ea perpendicular to the truss. Determine F; and Fn. A 1250 4.5 kN 30°
SITUATION 4: Three cables are used to tether a balloon as shown in the figure. Knowing that the balloon exerts a 1000 N vertical force, and the wind exerts a 100 N force along positive x-direction both acting at point A. Which of the following most nearly gives the force at cable AB, in N? (Answer: 436.35) Which of the following most nearly gives the force at cable AD, in N? (Answer: 247.67) Which of the following most nearly gives the force at cable AC, in N? (Answer: 458.97)
Activity 3. From a bar subjected by an axial force P, Draw the components of P acting on the inclined plane. 30° SHAD NAO FAS VIN
The flanged steel cantilever beam with riveted bracket is subjected to the couple and two forces shown, and their effect on the design of the attachment at A must be determined. Replace the two forces and couple by an equivalent couple M and resultant R at A. The couple is positive if counterclockwise, negative if clockwise. A Answers: M = i R=(i L--x -2.197 1.46 m. 1.3 460 N.m 5 0.42 m 9 kN.m 1.97 KN i+ i 1.4 79⁰ 1.07 KN 0.13 m 0.13 m j) kN
3.30 For the truss and loading shown, determine the resultant of the loads and the distance from point A to its line of action. R d 4 kips 3 kips 2 kips D E 6 ft В 8 ft 8 ft 8 ft 8 ft
Required information Problem 02.003 - Addition of planar forces applied to a hook NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Two forces P and Q are applied as shown at point A of a hook support. ट 20°i 35° Problem 02.003.b - Resultant of forces applied to a hook using the triangle rule Knowing that P = 75 N and Q = 195 N, determine graphically the magnitude and direction of their resultant using the triangle rule. The magnitude of the resultant is The direction of the resultant is 245.8 N. 14.5°
%VY li. o HW#6_Ch.4 (Part C... 4.9 4-154. Replace the distributed loading by an equivalent resultant force and specify where its line of action intersects a horizontal lin +Dmonoured from A. 4-155. Replace the distributed loading by an equivalent resultant force and specify where its line of action intersects a vertical line along member BC, measured from C. 3 kN/m 3 m 2 kN/m 4 m Probs. 4-154/155 *415
Problem 6: Replace the given loading system by an equivalent resultant force and specify where the resultant's line of action intersects the member AB measured from A. 1.0 m -2.0 m- 0.5 m 05 m 20 kN 4 kN 10 kN 4.0 m
Q3: The flanged steel cantilever beam with riveted bracket is subjected to the couple and two forces shown, and their effect on the design of the attachment at A must be determined. Replace the two forces and couple by an equivalent couple .M and resultant force R at A A L. 1.5 m 500 N-m 0.5 m 2 kN 70° 1.2 kN 10.15 m 10.15 m
Knowing that the radius of each pulley is 130 mm and neglecting friction, external force is 297 N. Determine the internal forces at Points J and K of the frame shown. Solution: 1. FBD for frame and pulleys together: a. There are b. Sum moment about point c. Sum all the horizonal forces to zero, solve that Ax = = d. Sum all the vertical forces to zero, yield that Ay + By 2. FBD for Member AE: a. There are supports on the frame, they are both c. Thus By b. Sum moment about point = a. There are solve that Bx = d. Sum all the horizontal forces to zero, solve that Ex N; direction is pointing to the 3. FBD for AK to determine the internal forces on K: forces/reactions on the member AE, for a 2D body, this is statically a. There are forces/reactions on the AK; b. Sum axial forces to zero, solve that nominal force FK d. Sum moment about point and note that the tension force in the cable on D is c. Sum tangential forces to zero, solve that shear force VK = 4. FBD for BJ to determine the…
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