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Knowing that the radius of each pulley is 130 mm and neglecting friction, external force is 297 N. Determine the internal forces at Points J and K of the frame shown. Solution: 1. FBD for frame and pulleys together: a. There are b. Sum moment about point c. Sum all the horizonal forces to zero, solve that Ax= a. There are supports on the frame, they are both d. Sum all the vertical forces to zero, yield that Ay + By = 2. FBD for Member AE: c. Thus By = b. Sum moment about point , solve that By = a. There are a. There are d. Sum all the horizontal forces to zero, solve that Ex= 3. FBD for AK to determine the internal forces on K: forces/reactions on the AK; N; direction is pointing to the forces/reactions on the member AE, for a 2D body, this is statically b. Sum axial forces to zero, solve that nominal force FK = c. Sum tangential forces to zero, solve that shear force VK = d. Sum moment about point 4. FBD for BJ to determine the internal forces on J: forces/reactions on the AK; , and note that the tension force in the cable on D is all together there are N; direction is pointing to the b. Sum axial forces to zero, solve that nominal force FK = N; direction is pointing to the N; c. Sum tangential forces to zero, solve that shear force VK = N; direction is pointing to the , solve that bending moment on k is MK = N; direction is pointing to the N; direction is pointing to the reactions on the supports, for a 2D body, this is statically , solve that A, = d. Sum moment about point , solve that bending moment on J is MJ = N; direction is pointing to the + N; direction is pointing to the Nm; direction is pointing to the + ● Nm; direction is pointing to the N; direction is pointing to the 1.8m A D 0.8m K 0.8 m 0.8 m

Knowing that the radius of each pulley is 130 mm and neglecting friction, external force is 297 N. Determine the internal forces at Points J and K of the frame shown. Solution: 1. FBD for frame and pulleys together: a. There are b. Sum moment about point c. Sum all the horizonal forces to zero, solve that Ax= a. There are supports on the frame, they are both d. Sum all the vertical forces to zero, yield that Ay + By = 2. FBD for Member AE: c. Thus By = b. Sum moment about point , solve that By = a. There are a. There are d. Sum all the horizontal forces to zero, solve that Ex= 3. FBD for AK to determine the internal forces on K: forces/reactions on the AK; N; direction is pointing to the forces/reactions on the member AE, for a 2D body, this is statically b. Sum axial forces to zero, solve that nominal force FK = c. Sum tangential forces to zero, solve that shear force VK = d. Sum moment about point 4. FBD for BJ to determine the internal forces on J: forces/reactions on the AK; , and note that the tension force in the cable on D is all together there are N; direction is pointing to the b. Sum axial forces to zero, solve that nominal force FK = N; direction is pointing to the N; c. Sum tangential forces to zero, solve that shear force VK = N; direction is pointing to the , solve that bending moment on k is MK = N; direction is pointing to the N; direction is pointing to the reactions on the supports, for a 2D body, this is statically , solve that A, = d. Sum moment about point , solve that bending moment on J is MJ = N; direction is pointing to the + N; direction is pointing to the Nm; direction is pointing to the + ● Nm; direction is pointing to the N; direction is pointing to the 1.8m A D 0.8m K 0.8 m 0.8 m

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Knowing that the radius of each pulley is 130 mm and neglecting friction, external force is 297 N. Determine the internal forces at Points J and K of the frame shown. Solution: 1. FBD for frame and pulleys together: a. There are b. Sum moment about point c. Sum all the horizonal forces to zero, solve that Ax = = d. Sum all the vertical forces to zero, yield that Ay + By 2. FBD for Member AE: a. There are supports on the frame, they are both c. Thus By b. Sum moment about point = a. There are solve that Bx = d. Sum all the horizontal forces to zero, solve that Ex N; direction is pointing to the 3. FBD for AK to determine the internal forces on K: forces/reactions on the member AE, for a 2D body, this is statically a. There are forces/reactions on the AK; b. Sum axial forces to zero, solve that nominal force FK d. Sum moment about point and note that the tension force in the cable on D is c. Sum tangential forces to zero, solve that shear force VK = 4. FBD for BJ to determine the internal forces on J: forces/reactions on the AK; d. Sum moment about point = b. Sum axial forces to zero, solve that nominal force FK + ◆ ; all together there are = N; direction is pointing to the c. Sum tangential forces to zero, solve that shear force VK = N; direction is pointing to the N; , solve that bending moment on k is Mk N; direction is pointing to the N; direction is pointing to the N; direction is pointing to the reactions on the supports, for a 2D body, this is statically solve that Ay solve that bending moment on J is MJ = + N; direction is pointing to the N; direction is pointing to the ◆ Nm; direction is pointing to the = → Nm; direction is pointing to the N; direction is pointing to the ◆ ◆ 1.8 m 1m D 0.8 m K 0.8 m 0.8 m
Transcribed Image Text:Knowing that the radius of each pulley is 130 mm and neglecting friction, external force is 297 N. Determine the internal forces at Points J and K of the frame shown. Solution: 1. FBD for frame and pulleys together: a. There are b. Sum moment about point c. Sum all the horizonal forces to zero, solve that Ax = = d. Sum all the vertical forces to zero, yield that Ay + By 2. FBD for Member AE: a. There are supports on the frame, they are both c. Thus By b. Sum moment about point = a. There are solve that Bx = d. Sum all the horizontal forces to zero, solve that Ex N; direction is pointing to the 3. FBD for AK to determine the internal forces on K: forces/reactions on the member AE, for a 2D body, this is statically a. There are forces/reactions on the AK; b. Sum axial forces to zero, solve that nominal force FK d. Sum moment about point and note that the tension force in the cable on D is c. Sum tangential forces to zero, solve that shear force VK = 4. FBD for BJ to determine the internal forces on J: forces/reactions on the AK; d. Sum moment about point = b. Sum axial forces to zero, solve that nominal force FK + ◆ ; all together there are = N; direction is pointing to the c. Sum tangential forces to zero, solve that shear force VK = N; direction is pointing to the N; , solve that bending moment on k is Mk N; direction is pointing to the N; direction is pointing to the N; direction is pointing to the reactions on the supports, for a 2D body, this is statically solve that Ay solve that bending moment on J is MJ = + N; direction is pointing to the N; direction is pointing to the ◆ Nm; direction is pointing to the = → Nm; direction is pointing to the N; direction is pointing to the ◆ ◆ 1.8 m 1m D 0.8 m K 0.8 m 0.8 m
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