-28. Find the position of the mass, in meters, after t seconds. Your answer should be a function of the variable t with the general form c1eαtcos(βt)+c2eγsin(δt) α=(-1/2) β=sqrt(28)/4 γ=(-1/2) δ=sqrt(28)/4 c1=1 c2=? I helped you out as bes
A spring with a 2-kg mass and a damping constant 2 can be held stretched 0.5 meters beyond its natural length by a force of 2 newtons. Suppose the spring is stretched 1 meters beyond its natural length and then released with zero velocity.
In the notation of the text, what is the value c2 - 4mk? -28.
Find the position of the mass, in meters, after t seconds. Your answer should be a function of the variable t with the general form
c1eαtcos(βt)+c2eγsin(δt)
α=(-1/2)
β=sqrt(28)/4
γ=(-1/2)
δ=sqrt(28)/4
c1=1
c2=?
I helped you out as best I could, but I couldn't find the answer for the final arbitrary constant, could you help me find it. This is a differential equations question.
This is a calculus question.
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