A spring with a 2-kg mass and a damping constant 2 can be held stretched 2.5 meters beyond its natural length by a force of 7.5 newtons. Suppose the spring is stretched 5 meters beyond its natural length and then released with zero velocity, In the notation of the text, what is the value c² - 4mk? m²kg²/sec² Find the position of the mass, in meters, after t seconds. Your answer should be a function of the variable t with the general form c₁eat cos(pt) + c₂ert sin(St) α = B = Y = 8 = C1 = C₂ =

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