2/75 Electrons are emitted at A with a velocity u at the angle 0 into the space between two charged plates. The electric field between the plates is in the direction E and repels the electrons approaching the upper plate. The field produces an acceleration of the electrons in the E-direction of eE/m, where e is the electron charge and m is its mass. Determine the field strength E which will permit the electrons to cross one-half of the gap between the plates. Also find the distance s. mu? sin2 6 Ans. E = s = 26 cot 0 eb E b/2 Electron path b/2 A Electron source

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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2/75 Electrons are emitted at A with a velocity u at the
angle 0 into the space between two charged plates. The
electric field between the plates is in the direction E
and repels the electrons approaching the upper plate.
The field produces an acceleration of the electrons in
the E-direction of eElm, where e is the electron charge
and m is its mass. Determine the field strength E
which will permit the electrons to cross one-half of the
gap between the plates. Also find the distance s.
mu? sin? 6
Ans. E =
s = 2b cot 0
eb
E
b/2
Electron
path
b/2
Electron
source
Problem 2/75
Transcribed Image Text:2/75 Electrons are emitted at A with a velocity u at the angle 0 into the space between two charged plates. The electric field between the plates is in the direction E and repels the electrons approaching the upper plate. The field produces an acceleration of the electrons in the E-direction of eElm, where e is the electron charge and m is its mass. Determine the field strength E which will permit the electrons to cross one-half of the gap between the plates. Also find the distance s. mu? sin? 6 Ans. E = s = 2b cot 0 eb E b/2 Electron path b/2 Electron source Problem 2/75
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