2/75 Electrons are emitted at A with a velocity u at the angle 0 into the space between two charged plates. The electric field between the plates is in the direction E and repels the electrons approaching the upper plate. The field produces an acceleration of the electrons in the E-direction of eE/m, where e is the electron charge and m is its mass. Determine the field strength E which will permit the electrons to cross one-half of the gap between the plates. Also find the distance s. mu? sin2 6 Ans. E = s = 26 cot 0 eb E b/2 Electron path b/2 A Electron source
2/75 Electrons are emitted at A with a velocity u at the angle 0 into the space between two charged plates. The electric field between the plates is in the direction E and repels the electrons approaching the upper plate. The field produces an acceleration of the electrons in the E-direction of eE/m, where e is the electron charge and m is its mass. Determine the field strength E which will permit the electrons to cross one-half of the gap between the plates. Also find the distance s. mu? sin2 6 Ans. E = s = 26 cot 0 eb E b/2 Electron path b/2 A Electron source
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![2/75 Electrons are emitted at A with a velocity u at the
angle 0 into the space between two charged plates. The
electric field between the plates is in the direction E
and repels the electrons approaching the upper plate.
The field produces an acceleration of the electrons in
the E-direction of eElm, where e is the electron charge
and m is its mass. Determine the field strength E
which will permit the electrons to cross one-half of the
gap between the plates. Also find the distance s.
mu? sin? 6
Ans. E =
s = 2b cot 0
eb
E
b/2
Electron
path
b/2
Electron
source
Problem 2/75](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F07fe11fb-4ae3-4db8-bc08-ca3bbeb72418%2Fdbd7d11c-2201-4f92-87fc-499d3ffcba01%2F0lc7qk5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2/75 Electrons are emitted at A with a velocity u at the
angle 0 into the space between two charged plates. The
electric field between the plates is in the direction E
and repels the electrons approaching the upper plate.
The field produces an acceleration of the electrons in
the E-direction of eElm, where e is the electron charge
and m is its mass. Determine the field strength E
which will permit the electrons to cross one-half of the
gap between the plates. Also find the distance s.
mu? sin? 6
Ans. E =
s = 2b cot 0
eb
E
b/2
Electron
path
b/2
Electron
source
Problem 2/75
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