27. When 0.0500 mol of CH4 (g) burns, 40.1 kJ of heat is produced. What is the change in enthalpy (AH) in kJ for the following reaction: CH4 (g) + 202 (g) (a) +802 kJ/mol (b) -802 kJ/mol , CO₂ (g) + 2H₂O(g) + Heat (c) +40.1 kJ/mol (d) -40.1 kJ/mol

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter4: Energy And Chemical Reactions
Section4.4: Heat Capacity
Problem 4.4PSP
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### Example Problem: Calculating Enthalpy Change (ΔH)

**Problem:**
When 0.0500 mol of CH₄(g) burns, 40.1 kJ of heat is produced. What is the change in enthalpy (ΔH) in kJ for the following reaction?

\[
\text{CH}_4(\text{g}) + 2\text{O}_2(\text{g}) \longrightarrow \text{CO}_2(\text{g}) + 2\text{H}_2\text{O}(\text{g}) + \text{Heat}
\]

**Options:**
- (a) +802 kJ/mol
- (b) -802 kJ/mol
- (c) +40.1 kJ/mol
- (d) -40.1 kJ/mol

**Solution:**

Given:
- Heat produced by 0.0500 mol of CH₄(g) = 40.1 kJ

To find the ΔH for the reaction, we need to determine the heat produced per mole of CH₄(g).

1. Calculate heat produced per mole of CH₄(g):
\[
\text{Heat per mole} = \frac{\text{Total heat produced}}{\text{amount in moles}}
\]
\[
\text{Heat per mole} = \frac{40.1 \text{ kJ}}{0.0500 \text{ mol}}
\]

2. Perform the calculation:
\[
\text{Heat per mole} = \frac{40.1}{0.0500} = 802 \text{ kJ/mol}
\]

Since heat is produced, the enthalpy change (ΔH) is negative (exothermic reaction).

**Therefore, the correct answer is:**

- **(b) -802 kJ/mol**

### Explanation:

This calculation is essential in understanding the thermodynamics of chemical reactions. The negative sign indicates that energy is released to the surroundings when methane (CH₄) combusts.
Transcribed Image Text:### Example Problem: Calculating Enthalpy Change (ΔH) **Problem:** When 0.0500 mol of CH₄(g) burns, 40.1 kJ of heat is produced. What is the change in enthalpy (ΔH) in kJ for the following reaction? \[ \text{CH}_4(\text{g}) + 2\text{O}_2(\text{g}) \longrightarrow \text{CO}_2(\text{g}) + 2\text{H}_2\text{O}(\text{g}) + \text{Heat} \] **Options:** - (a) +802 kJ/mol - (b) -802 kJ/mol - (c) +40.1 kJ/mol - (d) -40.1 kJ/mol **Solution:** Given: - Heat produced by 0.0500 mol of CH₄(g) = 40.1 kJ To find the ΔH for the reaction, we need to determine the heat produced per mole of CH₄(g). 1. Calculate heat produced per mole of CH₄(g): \[ \text{Heat per mole} = \frac{\text{Total heat produced}}{\text{amount in moles}} \] \[ \text{Heat per mole} = \frac{40.1 \text{ kJ}}{0.0500 \text{ mol}} \] 2. Perform the calculation: \[ \text{Heat per mole} = \frac{40.1}{0.0500} = 802 \text{ kJ/mol} \] Since heat is produced, the enthalpy change (ΔH) is negative (exothermic reaction). **Therefore, the correct answer is:** - **(b) -802 kJ/mol** ### Explanation: This calculation is essential in understanding the thermodynamics of chemical reactions. The negative sign indicates that energy is released to the surroundings when methane (CH₄) combusts.
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