27 0.49 27 0.64 45. d = -20e0.74/40 46. d = -20e 0.8/40 Cos Cos 1600 1600 27 0.36 0.25 47. d = -30e 0.61/80 cos 48. d = -30e 0.51/70 cos 6400 4900 (e) 0.81 27 0.64 49. d = -15e 0.9/30 cos 50. d = -10e8/50 Cos 900 2500
27 0.49 27 0.64 45. d = -20e0.74/40 46. d = -20e 0.8/40 Cos Cos 1600 1600 27 0.36 0.25 47. d = -30e 0.61/80 cos 48. d = -30e 0.51/70 cos 6400 4900 (e) 0.81 27 0.64 49. d = -15e 0.9/30 cos 50. d = -10e8/50 Cos 900 2500
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
In Problems 45–50, the distance d (in meters) of the bob of a pendulum of mass m (in kilograms) from its rest position at time t (in seconds)
is given. The bob is released from the left of its rest position and represents a negative direction.
(a) Describe the motion of the object. Be sure to give the mass and damping factor.
(b) What is the initial displacement of the bob? That is, what is the displacement at t = 0?
(c) Graph the motion using a graphing utility.
(d) What is the displacement of the bob at the start of the second oscillation?
(e) What happens to the displacement of the bob as time increases without bound?
![27
0.49
27
0.64
45. d = -20e0.74/40
46. d = -20e 0.8/40
Cos
Cos
1600
1600
27
0.36
0.25
47. d = -30e 0.61/80 cos
48. d = -30e 0.51/70 cos
6400
4900
(e)
0.81
27
0.64
49. d = -15e 0.9/30
cos
50. d = -10e8/50
Cos
900
2500](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff5cb7fe3-6c83-44bc-83c2-617b78346fe8%2F8a6a3724-dfff-462a-81ff-9221f56cec15%2Fe5l648c_processed.png&w=3840&q=75)
Transcribed Image Text:27
0.49
27
0.64
45. d = -20e0.74/40
46. d = -20e 0.8/40
Cos
Cos
1600
1600
27
0.36
0.25
47. d = -30e 0.61/80 cos
48. d = -30e 0.51/70 cos
6400
4900
(e)
0.81
27
0.64
49. d = -15e 0.9/30
cos
50. d = -10e8/50
Cos
900
2500
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