25. The following model was fitted to data on 32 insurance companies:9 = 7.62 - 0.16xi + 1.23x2 R = 0.37(0.008) (0.496)where9 = price-earnings ratioXI = size of insurance company assets, in billions of dollarsx2 = dummy variable taking the value I for regional companies and 0 for national companiesThe numbers in parentheses under the coefficients are the estimated coefficient standard errors.a. Interpret the estimated coefficient on the dummy variable.b. Test against a two-sided alternative. the null hypothesis that the true coefficient on thedummy variable is 0.c. Test, at the 5% level, the null hypothesis B, = B2 = 0, and interpret your result.

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Answered: 25. The following model was fitted to…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Suppose u1 and uz are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. The data follows: m = 6, x = 115.6, s1 = 5.03, n = 6, y = 129.9, and s2 = 5.38. Calculate a 95% CI for the difference between true average stopping distances for cars equipped with system 1 and cars equipped with system 2. (Round your answers to two decimal places.) In USE SALT Does the interval suggest that precise information about the value of this difference is available? Because the interval is so narrow, it appears that precise information is available. Because the interval is so narrow, it appears that precise information is not available. o Because the interval is so wide, it appears that precise information is not available. o Because the interval is so wide, it appears that precise information is available.
A large automobile insurance company selected samples of single and married male policyholders and recorded the number who made an insurance claim over the preceding three-year period. Z-value p-value Single Policyholders n₁ = 440 Number making claims = 88 a. Use a = 0.05. Test to determine whether the claim rates differ between single and married male policyholders. (to 2 decimals) (to 4 decimals) X Married Policyholders n2 = 840 Number making claims 126 We can conclude ✔ that there is the difference between claim rates. b. Provide a 95% confidence interval (to 4 decimals) for the difference between the proportions for the two populations. Enter negative answer as negative number. X * )
8.6 Cherry Trees: Timber yield is approximately equal to the volume of a tree, however, this value is difficult to measure without first cutting the tree down. Instead, other variables, such as height and diameter, may be used to predict a tree's volume and yield. Researchers wanting to understand the relationship between these variables for black cherry trees collected data from 31 such trees in the Allegheny National Forest, Pennsylvania. Height is measured in feet, diameter in inches (at 54 inches above ground), and volume in cubic feet. (Hand, 1994) Estimate Std. Error t value P(>|t|) (Intercept) -57.99 8.64 -6.71 0.00 height 0.34 0.13 2.61 0.01 diameter 4.71 0.26 17.82 0.00
You want to conduct a study on the proportion of Penn State students who miss class when it is raining. Suppose here is the data you collect for students who live on-campus versus students who live off-campus: Never Miss Sometimes Miss Always Miss On-Campus 20 12 13 Off-Campus 45 14 22 a. For on-campus students (only), estimate the true difference in proportions for those who never miss class versus those who always miss class, when it is raining. Place a bound on the error of estimation. b. Estimate the true difference between the proportions of on-campus students who always miss class versus the proportion of off-campus students who always miss class, when it is raining. Place a bound on the error of estimation.
Data was collected on the number of pairs of shoes people own and the number of miles they walk per week. 2 = 0.38 . Then 38% of the variation in miles walked can be explained by the linear relationship between the in the number of shoes owned and the miles walked. 62% is attributable to other factors. false true
Patrick is studying the relationship between the number of employees per department and the monthly overtime per department and has collected the data shown in the table. The line of best fit for the data is yˆ=0.135x+36.6. Number of Employees 6080100120 Monthly Overtime (Hours) 45475053 According to the line of best fit, what would be the predicted monthly overtime for a department that had 122 employees? Provide your answer below: The predicted monthly overtime is hours.
Q1. A study was conducted to investigate the relationship between premature birth and mental development at 12 months. The infant's birth weight was used as an index of prematurity. At age 12 months, the child's mental development was recorded. The results are shown below (the weights are in pounds): Birth 4 6 7 8 Weight(x) Developmental 85 Quotients(y) 88 87 94 96 Summary: n = 5, £x=30, £x² = 190, Ey= 450, Ey² = 40590, Exy = 2728 . a. Find the least square prediction equation, y on x. b. Obtain a 95% confidence interval for the average value of y when x 6.5 (i.e., a C.I. for E(y|x= 6.5)). c. Obtain the coefficient of correlation (r) and interpret the result. d. Test the hypothesis that H, :p= 0 vs. H, : p0. Use a =0.05.
10. 18.30 Temperatures are measured at various points on a heated plate (Table P18.30). Estimate the temperature at (a) x = 4, y = 3.2, and (b) x = 4.3, y = 2.7. TABLE P18.30 Temperature (°C) at various points on a square heated plate. x = 0 x = 2 y = 0 y 2 y = 4 y=6 y 8 100.00 85.00 70.00 55.00 40.00 90.00 64.49 48.90 38.78 35.00 x = 6 70.00 48.15 35.03 30.39 27.07 30.00 25.00 x = 4 80.00 53.50 38.43 x = 8 60.00 50.00 40.00 30.00 20.00
For the following situations, identify the type of variable (qualitative, nominal, ordinal, quantitative, discrete, continuous, interval, ratio), multiple types may apply. 1) Data of weight gain of rats fed only junk food for four weeks in an experiment. 2) Data collected from the order that students finsih their exam. 3) Time it takes for a car battery to die
Listed below are pulse rates (beats per minute) from samples of adult males and females. Does there appear to be adifference? Find the coefficient of variation for each of the two samples; then compare the variation. A. The coefficient of variation for the male pulse rates iS (Type an integer or decimal rounded to one decimal place as needed.) B. The coefficient of variation for the female pulse rates is (Type an integer or decimal rounded to one decimal place as needed.)
Q1. A psychologist conducted a study on the relationship between introversion and shyness. The values are results for scales of introversion and shyness. High positive scores on each scale indicate high introversion or shyness; and high negative scores indicate low introversion or shyness. Data collected from 10 people as follows: Introversion 4 -7 -1 0 6 7 -4 -9 -5 8 Shyness 11 -7 -1 -3 0 7 -1 -8 -1 5 a) Compute the correlation coefficient relating introversion and shyness scores. b) Find the regression equation which predicts introversion from shyness. c) What introversion score would you predict from a shyness score of 7?
1. What is the value of the slope of the best fit trends line for the relationship between TDD and the depth of the active layer. 2. If α = 0.05, is this slope statistically significant? (yes/no) 3. Compute a new variable that states the depth of the active layer in inches. The conversion formula is: (depth in inches) = (depth in centimetres) / 2.54 What is the mean depth of the active layer, measured in inches?

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