25. CS2(g) + 4 H2(g) → CHA(g) + 2 H₂S(g) at 298 K and 1 atm A. Calculate AHORxn for the above reaction, using the AH2, values in your references. B. Is this reaction exothermic or endothermic? C. Will it favor spontaneity based on enthalpy?

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25 all sections please.
25. CS2(g) + 4 H2(g) → CH4(g) + 2 H₂S(g) at 298 K and 1 atm
A. Calculate AHORxn for the above reaction, using the AH, values in your
references.
B. Is this reaction exothermic or endothermic?
C. Will it favor spontaneity based on enthalpy?
D. What would you predict the sign of ASORxn to be. Give your reasoning.
E. Calculate the ASORxn using the Sº values in your references.
F. Did your result match your prediction?
G. Calculate AGORxn using the Gibbs Free Energy equation.
9
Transcribed Image Text:25. CS2(g) + 4 H2(g) → CH4(g) + 2 H₂S(g) at 298 K and 1 atm A. Calculate AHORxn for the above reaction, using the AH, values in your references. B. Is this reaction exothermic or endothermic? C. Will it favor spontaneity based on enthalpy? D. What would you predict the sign of ASORxn to be. Give your reasoning. E. Calculate the ASORxn using the Sº values in your references. F. Did your result match your prediction? G. Calculate AGORxn using the Gibbs Free Energy equation. 9
H. Calculate AGORxn using the AGº, values in your references.
I. Is the reaction spontaneous at this temp? Give your reasoning.
J. Is the reaction spontaneous at all temps? If not, calculate the temperature at
which it switches to being non-spontaneous.
Transcribed Image Text:H. Calculate AGORxn using the AGº, values in your references. I. Is the reaction spontaneous at this temp? Give your reasoning. J. Is the reaction spontaneous at all temps? If not, calculate the temperature at which it switches to being non-spontaneous.
Expert Solution
Step 1

a.) ∆H°rxn can be calculated using the standard heat of formation ( ∆H°f )  values of each molecule involved in reaction.

b.) If ∆H°rxn is negative then reaction would be Exothermic.

  If ∆H°rxn is positive then reaction would be Endothermic. 

C) For reaction to be spontaneous in terms of enthalpy, there should be release in energy. That means ∆H°rxn should be negative. 

 

 

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