25. A radiograph made with an exposure of 12 mA per minute has a density of 0.8 in the area of interest. It is desired to increase the density to 2.0 in this area. By reference to a characteristic curve of the film, it is found that the difference in log e between a density of 0.8 and 2.0 is 0.76. The antilogarithm of log 0.76 is 5.8 (relative exposure factor). What must the new exposure time be to produce a radiograph with a density of 2.0, assuming the first exposure time was 1 minute?
25. A radiograph made with an exposure of 12 mA per minute has a density of 0.8 in the area of interest. It is desired to increase the density to 2.0 in this area. By reference to a characteristic curve of the film, it is found that the difference in log e between a density of 0.8 and 2.0 is 0.76. The antilogarithm of log 0.76 is 5.8 (relative exposure factor). What must the new exposure time be to produce a radiograph with a density of 2.0, assuming the first exposure time was 1 minute?
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Transcribed Image Text:25. A radiograph made with an exposure of 12 mA per minute has a density of 0.8 in the area of
interest. It is desired to increase the density to 2.0 in this area. By reference to a characteristic curve of
the film, it is found that the difference in log e between a density of 0.8 and 2.0 is 0.76. The
antilogarithm of log 0.76 is 5.8 (relative exposure factor). What must the new exposure time be to
produce a radiograph with a density of 2.0, assuming the first exposure time was 1 minute?
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