25. A newspaper conducted a statewide survey concerning the race for state senator. The newspaper took a randomsample (assume it is an SRS) of 1000 registered voters and found that 460 would vote for the Republicancandidate. Let p represent the proportion of registered voters in the state who would vote for the Republicancandidate. The best point estimate for a 95% confidence interval for p is(a) 0.34(c) 0.46(b) 460(e) 1.96(d) 1000

Given that, Let x be the registered voters in the sate who would vote for the republican candidate =…

Answered: 25. A newspaper conducted a statewide…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Example 8.11 For a class project, a political science student at a large university wants to estimate the percent of students who are registered voters. He surveys 500 students and finds that 300 are registered voters. Compute a 90% confidence interval for the true percent of students who are registered voters, and interpret the confidence interval.
A company is carrying out a consumer satisfaction survey for two of its products, product A and product B. The company believes that product A receives a higher proportion of satisfied customers than product B. Out of the 80 product A customers surveyed, 52 said they were satisfied with the product and out of the 100 product B customers surveyed, 42 said they were satisfied with the product. Use these sample statistics to compare the proportion of product A customers that are satisfied, p 1, and the proportion of product B customers that are satisfied, p 2. i) Carry out a hypothesis test for a significant difference between the two population proportions, at significance level α = 0.05. The hypotheses being tested are: H 0: p 1 - p 2 = 0 H a: p 1 - p 2 ≠ 0. Complete the test by filling in the blanks in the following:An estimate of the difference in population proportions is .The standard error is (3 dec places).The distribution is (examples: normal / t12 /…
Construct a 95% confidence interval for p1 - p2 for a survey that finds 30% of 240 males and 41% of 200 females are opposed to the death penalty. Group of answer choices a.(-0.200, -0.021) b.(-1.532, 1.342) c.(-1.324, 1.512) d.(-0.561, 0.651)
A random sample of 1026 adults in a certain large country was asked "Do you pretty much think televisions are a necessity or a luxury you could do without?" Of the 1026 adults surveyed, 533 indicated that televisions are a luxury they could do without. Complete parts (a) through (e) below. (a) Obtain a point estimate for the population proportion of adults in the country who believe that televisions are a luxury they could do without. A p= (Round to three decimal places as needed.)
A political researcher takes a survey of 310 randomly selected registered voters in Orlando, and each person was asked who they plan on voting for in the 2024 presidential election. 110 said they plan on voting for Candidate A, 185 said they plan on voting for Candidate B, and 15 were unsure or plan to vote for another candidate. The researcher wants to construct a 95% confidence interval for the proportion of all registered voters in Orlando who plan to vote for Candidate B. What is the point estimate? Round final answer to 3 decimal places.
The Substance Abuse and Mental Health Services Administration (SAMHSA, 2017) estimates that 10.9% of the population of the United States age 18–24 had an episode of depression in the previous 12 months. Suppose a researcher takes a random sample of 225 United States adults aged 18–24. Determine the value of the sample proportion, p, such that 5% of samples of 225 United States adults age 18–24 are greater than p. You may find software or a z-table useful. Give your answer precise to three decimal places. p = II
6. A researcher takes a sample of people, and asks them how they would vote for president. When she creates her confidence interval, she has a standard error of .082. If she wanted to get a smaller standard error, what could she do? Group of answer choices Ask a different research question. Take a smaller sample. Take a larger sample. None of the above would create a smaller standard error.
A local radio randomly selects 500 of its listeners. Listeners are offered to enter a competition where the price is a concert ticket. Among these 500 subscribers, 240 accept the promotional offer. The interval (45.76%, 50.23%) is a 95%-confidence interval for what quantity? a. the percentage of listeners in the sample who would accept the invitation to enter the competition b. the percentage of all listeners who would accept the invitation to enter the competition
The results of a recent poll on the preference of voters regarding the presidential candidates are shown below. Voters Surveyed Voters Favoring This Candidate Candidate A 200 150 Candidate B 300 195 Find a 95% confidence interval estimate for the difference between the proportions of voters favoring each candidate.
I need the answer as soon as possible
A real estate agent wishes to determine whether tax assessors and real estate appraisers agree on the values of homes. Random sample of the two groups appraised 10 homes. The data are shown here. At a = 0.05, is there a significant difference in the values of the homes for each group? (c) Real estate appraisers Tax assessors x1 = RM 83,256 S1 = RM 3,256 n, = 10 x2 = RM 88,354 S2 = RM 2,341 %3D n2 = 10

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