24R) The density of silver is 10.5 g/cm3. A piece of silver with a mass of 61.3 g would occupy a volume of cm3.

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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### Question 24R) 
The density of silver is 10.5 g/cm³. A piece of silver with a mass of 61.3 g would occupy a volume of ________ cm³.

#### Options:
A) 0.171

B) 644

C) 10.5

D) 0.00155

E) 5.84

---

### Explanation:

To find the volume (V) that a certain mass (m) of silver occupies given its density (d), use the formula:

\[ V = \frac{m}{d} \]

Given:
- \( m = 61.3 \) g
- \( d = 10.5 \) g/cm³

Plugging in the values:

\[ V = \frac{61.3 \text{ g}}{10.5 \text{ g/cm}³} = 5.84 \text{ cm}³ \]

Therefore, the correct answer is **E) 5.84**.

---

This question can help students understand the relationship between mass, volume, and density, and how to apply the density formula to solve real-world problems.
Transcribed Image Text:### Question 24R) The density of silver is 10.5 g/cm³. A piece of silver with a mass of 61.3 g would occupy a volume of ________ cm³. #### Options: A) 0.171 B) 644 C) 10.5 D) 0.00155 E) 5.84 --- ### Explanation: To find the volume (V) that a certain mass (m) of silver occupies given its density (d), use the formula: \[ V = \frac{m}{d} \] Given: - \( m = 61.3 \) g - \( d = 10.5 \) g/cm³ Plugging in the values: \[ V = \frac{61.3 \text{ g}}{10.5 \text{ g/cm}³} = 5.84 \text{ cm}³ \] Therefore, the correct answer is **E) 5.84**. --- This question can help students understand the relationship between mass, volume, and density, and how to apply the density formula to solve real-world problems.
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