24. Which of the following bases would make an E2 reaction occur at the fastest rate? ONa KCI KBr SK ONa II III IV V a. I d. IV b. II e. V C. II
24. Which of the following bases would make an E2 reaction occur at the fastest rate? ONa KCI KBr SK ONa II III IV V a. I d. IV b. II e. V C. II
Organic Chemistry
8th Edition
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Chapter21: Benzene And The Concept Of Aromaticity
Section: Chapter Questions
Problem 21.58P
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
Transcribed Image Text:**Question 24**: Which of the following bases would make an E2 reaction occur at the fastest rate?
**Options**:
- **I.** KCl
- **II.** KBr
- **III.** SK
Structures:
- **IV.** Sodium cyclopropoxide
- **V.** Sodium cyclopentoxide
**Answers**:
- **a.** I
- **b.** II
- **c.** III
- **d.** IV
- **e.** V (correct answer indicated)
**Explanation**:
The fastest E2 reaction is facilitated by the most suitable base, often one that is strong and bulky to promote elimination over substitution. In this case, option V (Sodium cyclopentoxide) is indicated as the correct answer likely because it forms a strong base. The cyclic structures (particularly larger rings) can help stabilize the transition state in the E2 mechanism more effectively than smaller, less hindered bases.
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