P-value - 0.088and24. The treatments and experimental units in the study arerespectively.O A. carbon dioxide levels; and the plantsO B. carbon dioxide levels; and the aquariumsO C. aquariums; and the plantsO D. plant height; and the aquariums For numbers 24-26: Aquascaping involves growing aquatic plants andaesthetically arranging them in an aquarium like a natural landscape. Success ofgrowing plants depends on several factors such as light condition, water pH, andcarbon dioxide level. It is of interest to determine if varying concentrations ofcarbon dioxide (0.5 ppm, 1.2 ppm, 1.5 ppm) introduced to an aquarium willpromote or deter an aquatic plants' growth. Ten aquariums with one-week oldplant were set-up and randomly assigned to each treatment. Below are the Routputs with 5% level of significance.data:0.5Wilk-Shapiro Test for Normalitydata: 1.2p-value = 0.324p-value = 0.2534data: 1.5p-value = 0.6369Bartlett test of homogeneity of variancesheight by carbon dioxidedata:Bartlett's K-squared 4.5623, df = 2, p-value = 0.1022Analysis of VarianceDf Sum Sq Mean Sq F value Pr (>F)carbon dioxide 2 88.73 44.37 6.131 0.0289 *Residuals750.657.24.Signif. codes: 0 ***** 0.001 **** 0.01 0.05 ¹.¹ 0.1 ¹ ¹ 1Kruskal-Wallis Rank Sum Testdata: height by carbon dioxide= 0.08868Kruskal-Wallis chi-squared = 4.8455, df = 2, p-value

Answered: 24. The treatments and experimental…

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN:9780547587776

Author:HOLT MCDOUGAL

Publisher:HOLT MCDOUGAL

Chapter1: Variables, Expressions, And Integers

Section1.5: Adding Integers

Problem 45E

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Tsunami Waves and BreakwatersThis is a continuation of Exercise 16. Breakwaters affect wave height by reducing energy. See Figure 5.30. If a tsunami wave of height H in a channel of width W encounters a breakwater that narrows the channel to a width w, then the height h of the wave beyond the breakwater is given by h=HR0.5, where R is the width ratio R=w/W. a. Suppose a wave of height 8 feet in a channel of width 5000feet encounters a breakwater that narrows the channel to 3000feet. What is the height of the wave beyond the breakwater? b. If a channel width is cut in half by a breakwater, what is the effect on wave height? 16. Height of Tsunami WavesWhen waves generated by tsunamis approach shore, the height of the waves generally increases. Understanding the factors that contribute to this increase can aid in controlling potential damage to areas at risk. Greens law tells how water depth affects the height of a tsunami wave. If a tsunami wave has height H at an ocean depth D, and the wave travels to a location with water depth d, then the new height h of the wave is given by h=HR0.25, where R is the water depth ratio given by R=D/d. a. Calculate the height of a tsunami wave in water 25feet deep if its height is 3feet at its point of origin in water 15,000feet deep. b. If water depth decreases by half, the depth ratio R is doubled. How is the height of the tsunami wave affected?
Cholesterol Cholesterol in human blood is necessary, but too much can lead to health problems. There are three main types of cholesterol: HDL (high-density lipoproteins), LDL (low-density lipoproteins), and VLDL (very low-density lipoproteins). HDL is considered “good” cholesterol; LDL and VLDL are considered “bad” cholesterol. A standard fasting cholesterol blood test measures total cholesterol, HDL cholesterol, and triglycerides. These numbers are used to estimate LDL and VLDL, which are difficult to measure directly. Your doctor recommends that your combined LDL/VLDL cholesterol level be less than 130 milligrams per deciliter, your HDL cholesterol level be at least 60 milligrams per deciliter, and your total cholesterol level be no more than 200 milligrams per deciliter. (a) Write a system of linear inequalities for the recommended cholesterol levels. Let x represent the HDL cholesterol level, and let y represent the combined LDL VLDL cholesterol level. (b) Graph the system of inequalities from part (a). Label any vertices of the solution region. (c) Is the following set of cholesterol levels within the recommendations? Explain. LDL/VLDL: 120 milligrams per deciliter HDL: 90 milligrams per deciliter Total: 210 milligrams per deciliter (d) Give an example of cholesterol levels in which the LDL/VLDL cholesterol level is too high but the HDL cholesterol level is acceptable. (e) Another recommendation is that the ratio of total cholesterol to HDL cholesterol be less than 4 (that is, less than 4 to 1). Identify a point in the solution region from part (b) that meets this recommendation, and explain why it meets the recommendation.
Find the values of x in each proportion: a x6=3x c 6x+4=2x+2 b x53=2x37 d x+35=x+57 e x2x5=2x+1x1 g x1x+2=103x2 f x(x+5)4x+4=95 h x+72=x+2x2
A dietitian wishes to see if a person’s cholesterol level will change if the diet is supplemented by a certain mineral. Five randomly selected subjects were pre-tested, and then they took the mineral supplement for a 6-week period. The Cholesterol level before and after taking the mineral supplements is shown in the table below. (Cholesterol level is measured in milligrams per deciliter). Table is attached Questions: If X1 is a normal variate with mean 2 and standard deviation 4 and X2 is a normal variate with mean 3 and standard deviation 9, then find E[X1 - 2X2] and Var(X1 - 2X2) The confidence level can be viewed as the amount of risk that an analyst will accept when making a decision (State True or False) You find a 90% confidence interval for true average thiamin content in oats for a given sample as (2.4,7.8) and you interpret the confidence interval as: I can be highly confident that 90% of the oats in the sample will have thiamin content between 2.4 and 7.8 (State True or…
Rivers in North Carolina contain small concentrations of mercury that can accumulate in fish over their lifetimes. The concentration of mercury in fish tissue can be obtained by catching fish and sending samples to a lab for analysis. A study was conducted on fish from the Waccamaw and Lumber Rivers to investigate mercury levels in tissues of largemouth bass. At several stations along each river a group of fish were caught, weighed and measured; in addition a filet from each fish was sent to a lab so that the tissue concentration of mercury could be determined. In all, 171 fish were caught at 15 different research stations along the Waccamaw and Lumber Rivers. Data from fish caught at one of these stations is shown in the following table: length weight 1616 47.0 1862 48.7 2855 55.7 1199 45.2 1320 44.7 1225 43.8 870 38.5 1455 45.8 1220 44.0 1033 40.4 Compute the correlation between length and weight for these fish. (Assume the correlation conditions have been…
Rivers in North Carolina contain small concentrations of mercury that can accumulate in fish over their lifetimes. The concentration of mercury in fish tissue can be obtained by catching fish and sending samples to a lab for analysis. A study was conducted on fish from the Waccamaw and Lumber Rivers to investigate mercury levels in tissues of largemouth bass. At several stations along each river a group of fish were caught, weighed and measured; in addition a filet from each fish was sent to a lab so that the tissue concentration of mercury could be determined. In all, 171 fish were caught at 15 different research stations along the Waccamaw and Lumber Rivers. Data from fish caught at one of these stations is shown in the followinng table: length weight 1616 47.0 48.7 1862 2855 55.7 45.2 1199 1320 44.7 1225 43.8 870 38.5 1455 45.8 1220 44.0 1033 40.4 Compute the correlation between length and weight for these fish. (Assume the correlation conditions have been satisfied and round your…
Rivers in North Carolina contain small concentrations of mercury that can accumulate in fish over their lifetimes. The concentration of mercury in fish tissue can be obtained by catching fish and sending samples to a lab for analysis. A study was conducted on fish from the Waccamaw and Lumber Rivers to investigate mercury levels in tissues of largemouth bass. At several stations along each river a group of fish were caught, weighed and measured; in addition a filet from each fish was sent to a lab so that the tissue concentration of mercury could be determined. In all, 171 fish were caught at 15 different research stations along the Waccamaw and Lumber Rivers. Data from fish caught at one of these stations is shown in the following table: length weight 1616 47.0 1862 48.7 2855 55.7 1199 45.2 1320 44.7 1225 43.8 870 38.5 1455 45.8 1220 44.0 1033 40.4 Compute the correlation between length and weight for these fish. (Assume the correlation conditions have been…
3. Consider a gas in a piston-cylinder device in which the temperature is held constant. As the volume of the device was changed, the pressure was meas- ured. The volume and pressure values are reported in the following table: Volume, m Pressure, kPa, when I = 300 K 1 2494 2 1247 3 831 4. 623 5 499 416 (a) Usc lincar interpolation to cstimate the pressure when the volume is 3.8 m. (b) Usc cubic spline interpolation to estimate the pressurc when the vol umc is 3.8 m'. (c) Usc lincar interpolation to cstimate the volume if the pressure is meas- urcd to be 1000 kPa. (d) Usc cubic spline interpolation to estimate the volume if the pressure is mcasured to be 1000 kPa.
A mixture of sucrose and water was heated on a hot plate, and the temperature (in "C) was recorded each minute for 20 minutes by three thermocouples. The results are shown in the following table. Time I1 Iz I3 20 18 21 18 22 11 29 32 37 36 10 64 11 72 12 79 80 13 84 74 75 14 82 87 78 15 87 93 88 16 98 90 91 17 103 100 103 18 101 98 109 19 103 103 107 20 102 103 104 Compute the least-squares line for estimating the temperature as a function of time, using T, as the value for temperature. a. b. Compute the least-squares line for estimating the temperature as a function of time, using T, as the value for temperature. Compute the least-squares line for estimating the temperature as a function of time, using T, as the value for temperature. C. It is desired to compute a single line to estimate temperature as a function of time. One person suggests averaging the three slope estimates to obtain a single slope estimate, and averaging the three intercept estimates to obtain a single intercept…
Rapid drainage of floodwater is crucial to prevent damage during heavy rains. Several designs for a drainage canal were considered for a certain city. Each design was tested five times, to determine how long it took to drain the water reservoir. The following table presents the drainage times, in minutes. Channel Type Drainage Time 1 41.5 43.2 50.2 41.2 24.2 2 38.8 48.2 51.0 38.1 25.2 3 32.7 33.5 35.0 22.7 24.7 4 26.5 30.7 33.1 23.8 26.7 5 45.1 47.3 48.4 37.1 40.0 Can you conclude that there is a difference in the mean drainage times for the different channel designs? Use the =α0.01 level of significance and the ANOVA table shown below. One-way ANOVA: Drainage Source DF SS MS F P Channel 4 961.7896 240.4474 4.5623 0.0088 Error 20 1054.052 52.7026 Total 24 2015.8416 Is…
Three different corrosion-resistant coatings are being considered for use on iron pipes. Ten pieces of pipe are marked off in six equal segments. For each pipe, two segments received coating A, two received coating B, and the remaining two received coating C. The pipes were placed in a corrosive environment for a period of time; then the depth of the deepest pit (in mm) caused by corrosion was measured for each segment on each pipe. The effect of interest is the coating; the pipe is a blocking factor, and there were two replications on each pipe. The following sums of squares were calculated: sum of squares for blocks = 11.2, sum of squares for treatments = 4.8, sum of squares for interactions = 18.4, total sum of squares = 44.7. a) Construct an ANOVA table. You may give ranges for the P-values. b) Are the assumptions for a randomized complete block design satisfied? Explain. c) Does the ANOVA table provide evidence that mean pit depth differs among coatings? Explain.
Rapid drainage of floodwater is crucial to prevent damage during heavy rains. Several designs for a drainage canal were considered for a certain city. Each design was tested five times, to determine how long it took to drain the water reservoir. The following table presents the drainage times, in minutes. Channel Type Drainage Time 1 41.4 43.4 50.0 40.9 24.1 24.2 2 38.7 48.3 51.3 38.4 25.0 29.2 3 32.7 33.8 34.4 22.6 24.5 30.0 4 26.1 31.0 33.4 23.6 26.5 31.7 5 44.7 47.0 48.6 36.9 38.9 45.9 Construct an ANOVA table. Round your answers to four decimal places. One-way ANOVA: Drainage Time Source DF SS MS F P Minutes Error Total

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24. The treatments and experimental units in the study are respectively. O A. carbon dioxide levels; and the plants O B. carbon dioxide levels; and the aquariums C. aquariums; and the plants O D. plant height, and the aquariums 0.088 and