24. Draw the major organic product generated in the reaction below. Br2, CC14 ?

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**Question 24:**

Draw the major organic product generated in the reaction below.

**Reactants and Conditions:**

- The starting molecule is a hydrocarbon with two alkene (double bond) groups.
- The reagents used are Br\(_2\) (bromine) and CCl\(_4\) (carbon tetrachloride).

**Reaction Type:**

This is an electrophilic addition reaction involving bromine. In this reaction, bromine adds across the double bonds of the hydrocarbon, resulting in the formation of a dibromo product.

**Products:**

The major product will be the result of bromine atoms adding to both carbons involved in the double bonds. 

**Diagram Explanation:**

- The reactant is shown as a linear alkene with one of its sides substituted by a methyl group.
- After the reaction, bromine atoms will add to each carbon of the double bonds, transforming the alkene features into dibromoalkanes.

**Key Concepts:**

- The reaction follows Markovnikov's rule, where the bromine adds to the alkene carbons in a manner that results in the most stable carbocation intermediate.
- The solvent, CCl\(_4\), is non-polar and does not participate in the reaction but provides a medium for the bromine to dissolve and react.
Transcribed Image Text:**Question 24:** Draw the major organic product generated in the reaction below. **Reactants and Conditions:** - The starting molecule is a hydrocarbon with two alkene (double bond) groups. - The reagents used are Br\(_2\) (bromine) and CCl\(_4\) (carbon tetrachloride). **Reaction Type:** This is an electrophilic addition reaction involving bromine. In this reaction, bromine adds across the double bonds of the hydrocarbon, resulting in the formation of a dibromo product. **Products:** The major product will be the result of bromine atoms adding to both carbons involved in the double bonds. **Diagram Explanation:** - The reactant is shown as a linear alkene with one of its sides substituted by a methyl group. - After the reaction, bromine atoms will add to each carbon of the double bonds, transforming the alkene features into dibromoalkanes. **Key Concepts:** - The reaction follows Markovnikov's rule, where the bromine adds to the alkene carbons in a manner that results in the most stable carbocation intermediate. - The solvent, CCl\(_4\), is non-polar and does not participate in the reaction but provides a medium for the bromine to dissolve and react.
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