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24 Which of the equations are perpendicular to y = 8x + 1? Circle your answers. M. y − 1 = (x+3) N. y-2=-8(x - 1) P. 8y = -4x S. 8x+y = 13 V. y-8= 4x Q. x = -8 T. x+8y=-3 W. y = -x + 5 O. -8y = x + 2 R. y + 4 = 8(x+7) U. y = -1/ X. A line that goes through (3,2) and (-5,-6)

24 Which of the equations are perpendicular to y = 8x + 1? Circle your answers. M. y − 1 = (x+3) N. y-2=-8(x - 1) P. 8y = -4x S. 8x+y = 13 V. y-8= 4x Q. x = -8 T. x+8y=-3 W. y = -x + 5 O. -8y = x + 2 R. y + 4 = 8(x+7) U. y = -1/ X. A line that goes through (3,2) and (-5,-6)

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Which of the equations are perpendicular to y=8x+1 Please show work. Thank you
**Question 24: Identifying Perpendicular Equations** The task is to determine which of the given equations are perpendicular to the equation \( y = 8x + 1 \). You should circle the correct answers from the options provided. **Equations:** - **M.** \( y - 1 = \frac{1}{8}(x + 3) \) - **N.** \( y - 2 = -8(x - 1) \) - **O.** \(-8y = x + 2\) - **P.** \( 8y = -4x \) - **Q.** \( x = -8 \) - **R.** \( y + 4 = 8(x + 7) \) - **S.** \( 8x + y = 13 \) - **T.** \( x + 8y = -3 \) - **U.** \( y = -\frac{1}{8} \) - **V.** \( y - 8 = 4x \) - **W.** \( y = -\frac{1}{8}x + 5 \) - **X.** A line that goes through \((3, 2)\) and \((-5, -6)\) **Instructions:** To determine which equations are perpendicular, remember: - The original line has a slope of 8. - Perpendicular lines have slopes that are negative reciprocals. - Therefore, the slope of the perpendicular line should be \(-\frac{1}{8}\). Evaluate each option based on whether its slope is \(-\frac{1}{8}\).
Transcribed Image Text:**Question 24: Identifying Perpendicular Equations** The task is to determine which of the given equations are perpendicular to the equation \( y = 8x + 1 \). You should circle the correct answers from the options provided. **Equations:** - **M.** \( y - 1 = \frac{1}{8}(x + 3) \) - **N.** \( y - 2 = -8(x - 1) \) - **O.** \(-8y = x + 2\) - **P.** \( 8y = -4x \) - **Q.** \( x = -8 \) - **R.** \( y + 4 = 8(x + 7) \) - **S.** \( 8x + y = 13 \) - **T.** \( x + 8y = -3 \) - **U.** \( y = -\frac{1}{8} \) - **V.** \( y - 8 = 4x \) - **W.** \( y = -\frac{1}{8}x + 5 \) - **X.** A line that goes through \((3, 2)\) and \((-5, -6)\) **Instructions:** To determine which equations are perpendicular, remember: - The original line has a slope of 8. - Perpendicular lines have slopes that are negative reciprocals. - Therefore, the slope of the perpendicular line should be \(-\frac{1}{8}\). Evaluate each option based on whether its slope is \(-\frac{1}{8}\).
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