2310Ne is unstable. Complete the schematic energy diagram to the right by drawing in the protons and neutrons (with arrows representing spin directions) and predict how this nucleus will decay by specifying the final nucleus plus the two emitted particles. (This nucleus is small enough that electrostatic repulsion is not really significant.) Is the resulting nucleus stable?

2310Ne is unstable. Complete the schematic energy diagram to the right by drawing in the protons and neutrons (with arrows representing spin directions) and predict how this nucleus will decay by specifying the final nucleus plus the two emitted particles. (This nucleus is small enough that electrostatic repulsion is not really significant.) Is the resulting nucleus stable?

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Sr-90 (A=90, Z = 38) decays via B decay. Calculate the energy of the antineutrino (in keV) if the beta particle has a kinetic energy of (2.82x10^2) keV. %3D Note you can look the atomic masses up online or in the appendix of the textbook 1, Assume all the energy released are shared by the kinetic energy of the beta particle and antineutrino. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: х10 Answer
but they do get close enough together for the new nucleus. This is now called helium-3, consisting of two Finally, two helium-3 nuclei overcome their the repelled by the force, force to bind them into another and one repulsion and bind together via force, releasing two protons in the process. The final result is a stable nucleus of helium-4, consisting of two and two releases energy because the four protons we started with have resulting helium-4 nucleus, and because of the equation Select from the following word/equation bank to fill in each blank above: |Foras Gtttt • electric • gravitational • less • more • neutron(s) • proton(s) • strong • weak This entire process mass than the ||=1921 p F = que sin d E = (Am)e² Kmax λ=== Epheton-Eg * PEM 10:39 PM
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