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231 The half-life of isotope Pa is 32.76 years. Calculate the activity of 3e-06 g of this isotope in Bq and Ci: 91 A= 8055794618000X Bq and A= 217724178900 X Ci. Find the activity of this sample after 47 years: 805596785400( X Ci.

231 The half-life of isotope Pa is 32.76 years. Calculate the activity of 3e-06 g of this isotope in Bq and Ci: 91 A= 8055794618000X Bq and A= 217724178900 X Ci. Find the activity of this sample after 47 years: 805596785400( X Ci.

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### Radioactive Decay of Protactinium-231 #### Problem Statement The half-life of isotope \(\ce{^{231}_{91}Pa}\) is 32.76 years. Calculate the activity of \(3 \times 10^{-6}\) grams of this isotope in Bq and Ci: #### Solution First, we calculate the initial activity (A) of the sample: - Initial activity (A) in Bq: \( 8055794618000 \, \text{Bq} \) (shows a calculation but might indicate an error due to the "×" symbol) - Initial activity (A) in Ci: \( 217724178900 \, \text{Ci} \) (again showing a calculation with an indication of error) Now, determine the activity of this sample after 47 years: - Activity after 47 years: \( 8055967854000 \, \text{Ci} \) (also indicates an error due to the "×" symbol) ### Key Variables and Constants - **Half-life of \(\ce{^{231}_{91}Pa}\):** 32.76 years - **Sample mass:** \(3 \times 10^{-6} \, \text{g}\) - **Initial Activity:** - In Becquerel (Bq): \( 8055794618000 \, \text{Bq} \) - In Curie (Ci): \( 217724178900 \, \text{Ci} \) - **Activity after 47 years:** \( 8055967854000 \, \text{Ci} \) ### Graph/Diagram Explanation The image contains text and has no graphs or diagrams. ### Note to Students There are apparent errors marked by "×" in the calculations, signifying a place where re-evaluation or correction is required. Ensure to verify and recheck your computations as indicated in the solution above.
Transcribed Image Text:### Radioactive Decay of Protactinium-231 #### Problem Statement The half-life of isotope \(\ce{^{231}_{91}Pa}\) is 32.76 years. Calculate the activity of \(3 \times 10^{-6}\) grams of this isotope in Bq and Ci: #### Solution First, we calculate the initial activity (A) of the sample: - Initial activity (A) in Bq: \( 8055794618000 \, \text{Bq} \) (shows a calculation but might indicate an error due to the "×" symbol) - Initial activity (A) in Ci: \( 217724178900 \, \text{Ci} \) (again showing a calculation with an indication of error) Now, determine the activity of this sample after 47 years: - Activity after 47 years: \( 8055967854000 \, \text{Ci} \) (also indicates an error due to the "×" symbol) ### Key Variables and Constants - **Half-life of \(\ce{^{231}_{91}Pa}\):** 32.76 years - **Sample mass:** \(3 \times 10^{-6} \, \text{g}\) - **Initial Activity:** - In Becquerel (Bq): \( 8055794618000 \, \text{Bq} \) - In Curie (Ci): \( 217724178900 \, \text{Ci} \) - **Activity after 47 years:** \( 8055967854000 \, \text{Ci} \) ### Graph/Diagram Explanation The image contains text and has no graphs or diagrams. ### Note to Students There are apparent errors marked by "×" in the calculations, signifying a place where re-evaluation or correction is required. Ensure to verify and recheck your computations as indicated in the solution above.
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