Find the value of the derivative (if it exists) at the indicated extremum. (446) f(x)=-3x√x + 2 -4 -2 10 5 -5 -10- 2 Differentiate f(x) using the product rule. f'(x)=-3x Step 1 The minimum and maximum of a function on an interval are the extreme values, or extrema (the singular form of extrema is extremum), of the function on the interval. In the given problem, the extremum occurs when x = The specified function is f(x) = -3x√√x + 2 = −3x(x + 2)1/2, 4 ] (x + 2)²¹/2] + + (x + 2)¹/2. (

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Author:James Stewart
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Chapter1: Functions And Models
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Find the value of the derivative (if it exists) at the indicated extremum.
-4 4√6
(글,
f(x) =
3
== 3xVx + 2
-4
-2
10
-5
Submit Skip (you cannot come back)
- 10
Differentiate f(x) using the product rule.
f'(x) = -3x
Step 1
The minimum and maximum of a function on an interval are the extreme values, or extrema (the singular form of extrema is extremum), of the function on the interval. In the given problem, the extremum occurs
-4
when x =
3
The specified function is f(x) = -3x√√√x + 2 = − 3x(x + 2)¹/2.
2
1
- 2)²¹/²] +
(x + 2)
4
+ (x + 2)¹/2 . (
Transcribed Image Text:Find the value of the derivative (if it exists) at the indicated extremum. -4 4√6 (글, f(x) = 3 == 3xVx + 2 -4 -2 10 -5 Submit Skip (you cannot come back) - 10 Differentiate f(x) using the product rule. f'(x) = -3x Step 1 The minimum and maximum of a function on an interval are the extreme values, or extrema (the singular form of extrema is extremum), of the function on the interval. In the given problem, the extremum occurs -4 when x = 3 The specified function is f(x) = -3x√√√x + 2 = − 3x(x + 2)¹/2. 2 1 - 2)²¹/²] + (x + 2) 4 + (x + 2)¹/2 . (
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Find the value of the derivative (if it exists) at the indicated extremum.
(-4, 4√6)
3
f(x) = − 3x√x + 2
-4
-2
10
5
-5
- 10
Step 1
The minimum and maximum of a function on an interval are the extreme values, or extrema (the singular form of extrema is extremum), of the function on the interval. In the given problem, the extremum occurs
-4
when x =
3
The specified function is f(x) = −3x√x + 2
=
Differentiate f(x) using the product rule.
f'(x) = -3x
2
−3x(x + 2)¹/2.
1
|× (x + 2) ¹/²]
+ (x + 2)¹/2 .
Transcribed Image Text:Find the value of the derivative (if it exists) at the indicated extremum. (-4, 4√6) 3 f(x) = − 3x√x + 2 -4 -2 10 5 -5 - 10 Step 1 The minimum and maximum of a function on an interval are the extreme values, or extrema (the singular form of extrema is extremum), of the function on the interval. In the given problem, the extremum occurs -4 when x = 3 The specified function is f(x) = −3x√x + 2 = Differentiate f(x) using the product rule. f'(x) = -3x 2 −3x(x + 2)¹/2. 1 |× (x + 2) ¹/²] + (x + 2)¹/2 .
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