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Differentiate the function. f(x) = (6x² - 2x + 1) (4x² + 3x − Which of the following shows how to find the derivative of f(x)? OA. f'(x)=- (x (6x² - 2x +1 dx OC. f(x) = + 1) ) (4x² + 3x − 8) - (6x² - 2x + 1) [ (4x² + 3x-8)) dx d ○ B. f'(x)= [(a (8x²-2x+1)] (6x²-2x+1) - (4x² + 3x −8) (ax (4x² + 3x −8)) + dx (4x²+3x-8 +3x-8)² d (8x² - 2x + 1) (x (4x² + 3x-8)] - [ (x² - 2x + 1) ) (4x²-3x-6) + dx dx (6x² - 2x + 1)² OD. f'(x)=x (6x²- (√x (6x² − 2x + 1)) (4x² + 3x − 8) + (6x² - 2x + 1) (x (4x² + 3x − 8) dx The derivative of f(x) = (6x² − 2x + 1) (4x² + 3x - - +3x-8) is

Differentiate the function. f(x) = (6x² - 2x + 1) (4x² + 3x − Which of the following shows how to find the derivative of f(x)? OA. f'(x)=- (x (6x² - 2x +1 dx OC. f(x) = + 1) ) (4x² + 3x − 8) - (6x² - 2x + 1) [ (4x² + 3x-8)) dx d ○ B. f'(x)= [(a (8x²-2x+1)] (6x²-2x+1) - (4x² + 3x −8) (ax (4x² + 3x −8)) + dx (4x²+3x-8 +3x-8)² d (8x² - 2x + 1) (x (4x² + 3x-8)] - [ (x² - 2x + 1) ) (4x²-3x-6) + dx dx (6x² - 2x + 1)² OD. f'(x)=x (6x²- (√x (6x² − 2x + 1)) (4x² + 3x − 8) + (6x² - 2x + 1) (x (4x² + 3x − 8) dx The derivative of f(x) = (6x² − 2x + 1) (4x² + 3x - - +3x-8) is

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
Differentiate the function.
 
f(x)=6x2−2x+14x2+3x−8
 
The derivative of
f(x)=6x2−2x+14x2+3x−8
is
Differentiate the function. f(x) = (6x² - 2x + 1) (4x² + 3x - Which of the following shows how to find the derivative of f(x)? (x ( (6x² - 2x +1 + 1) ) (4x² + 3x - 8) - (6x² - 2x + 1) [ (4x² + 3x-8)) dx dx OA. f'(x)=- (4x²+3x-8 +3x-8) ² d ○ B. l'(x)= (& (8x²-2x+1)] (6x²-2x+1) - (4x² + 3x −8) (ax (4x² + 3x −8)) + dx OC. f'(x) = d (6x² - 2x+1) (x (4x² + 3x-6)] - [ (x²-2x+1)) (4x² + 3x-6) dx dx (6x² - 2x + 1)² ○d. Fox) = ( (8x²–2x+1)] (4x² + 3x −8) + (6x²³-2x + 1) ( (4x² + 3x-6)) O D. f'(x)= dx dx The derivative of f(x) = (6x² − 2x + 1) (4x² + 3x- - +3x-8) is
Transcribed Image Text:Differentiate the function. f(x) = (6x² - 2x + 1) (4x² + 3x - Which of the following shows how to find the derivative of f(x)? (x ( (6x² - 2x +1 + 1) ) (4x² + 3x - 8) - (6x² - 2x + 1) [ (4x² + 3x-8)) dx dx OA. f'(x)=- (4x²+3x-8 +3x-8) ² d ○ B. l'(x)= (& (8x²-2x+1)] (6x²-2x+1) - (4x² + 3x −8) (ax (4x² + 3x −8)) + dx OC. f'(x) = d (6x² - 2x+1) (x (4x² + 3x-6)] - [ (x²-2x+1)) (4x² + 3x-6) dx dx (6x² - 2x + 1)² ○d. Fox) = ( (8x²–2x+1)] (4x² + 3x −8) + (6x²³-2x + 1) ( (4x² + 3x-6)) O D. f'(x)= dx dx The derivative of f(x) = (6x² − 2x + 1) (4x² + 3x- - +3x-8) is
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