23.2a A slightly different mechanism for the decomposition of N₂O5 from that in Exercise 23.1b has also been proposed. It differs only in the last step, which is replaced by (3) NO+NO3 →→ NO₂ + NO₂ k3 Show that this mechanism leads to the same overall rate law.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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please only solve 23.2 a base on 23.1b, write in the detail please, cause i really don't know how to do it 

23.1b On the basis of the following proposed mechanism, account for the
experimental fact that the rate law for the decomposition 2 N₂O(g) →
4 NO₂(g) + O₂(g) is v = k[N₂O5].
k₁, k₁
k₂
(1) N₂O5NO2 + NO3
(2) NO₂ + NO3 → NO₂ + O₂ + NO
(3) NO+N₂O5 → NO₂ + NO₂ + NO₂
23.2a A slightly different mechanism for the decomposition of N₂O5 from
that in Exercise 23.1b has also been proposed. It differs only in the last step,
which is replaced by
(3) NO+NO3 → NO₂ + NO₂ k3
Show that this mechanism leads to the same overall rate law.
k₂
Transcribed Image Text:23.1b On the basis of the following proposed mechanism, account for the experimental fact that the rate law for the decomposition 2 N₂O(g) → 4 NO₂(g) + O₂(g) is v = k[N₂O5]. k₁, k₁ k₂ (1) N₂O5NO2 + NO3 (2) NO₂ + NO3 → NO₂ + O₂ + NO (3) NO+N₂O5 → NO₂ + NO₂ + NO₂ 23.2a A slightly different mechanism for the decomposition of N₂O5 from that in Exercise 23.1b has also been proposed. It differs only in the last step, which is replaced by (3) NO+NO3 → NO₂ + NO₂ k3 Show that this mechanism leads to the same overall rate law. k₂
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