23. What is the concentration (by mass) of the solute in a 25 °C solution prepared by dissolving 2.50x10 mol Na3PO4 in 1.000L of water (in ppm, ppb, and ppt, all to two decimal places)? A: 4.00 x 10- ppm; 4.10 × 10' ppb; 4.10×10* ppt
23. What is the concentration (by mass) of the solute in a 25 °C solution prepared by dissolving 2.50x10 mol Na3PO4 in 1.000L of water (in ppm, ppb, and ppt, all to two decimal places)? A: 4.00 x 10- ppm; 4.10 × 10' ppb; 4.10×10* ppt
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Chapter1: Chemical Foundations
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Transcribed Image Text:23. What is the concentration (by mass) of the solute in a 25 °C solution prepared by dissolving
2.50x10 mol Na PO4 in 1.000 L of water (in ppm, ppb, and ppt, all to two decimal places)?
ppm; 4.10 × 10' ppb; 4.10×10* ppt
A: 4.00 × 10
Expert Solution
Step 1
According to question
No. Of moles = 2.50× 10-7
Volume = 1L
So, Molarity = no. Of moles/Volume(L)
= 2.50×10-7 /1 = 2.50×10-7 M
Mass percentage =
Mass of solute/Mass of solution ×100
Mass of solute = 2.50×10-⁷ × 163.941 (molar mass of Na3PO4 )
= 4.098×10-⁵ g
Mass of solution = mass of solvent + water
= 4.098×10-⁵ + 1000 = 1000.00004g (density of water taken as 1g/ml)
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