23. The integral heats of solution at 18°C for the various solid modifications of calcium chloride in the indicated quantities of water are given by CaCl2(s) + 400 H;0(1) = CaCl2(400 H;0) СаCla - 2 H:0(s) + 398 H:0(1) — СаCli:(400 H:0) СаCli 4 H,0(8) + 396 H,0(1) — СаCl:(400 H,0) CaCl2 • 6 H,0(s) + 394 H;0(1) = CaCla(400 H;O) AH, = -17,990 cal AH: = -10,030 cal AH3 = -1830 cal ΔΗ %3D +4560 cal From these data find the heats of the following hydration reactions: (a) CaCl2(s) + 2 H¿0(1) = CaCl2 · 2 H,0(s) (b) СаCl; - 2 H0(8) + 2 H:0(1) (c) CaCl, · 4 H20(s) + 2 H¿0(1) = CaCl, · 6 H,0(s) (d) CaCl (s) + 6 H;0(1) CaClą · 4 H20(s) CaCl2 · 6 H,0(s)

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
Question

{THERMOCHEMISTRY)

23. The integral heats of solution at 18°C for the various solid modifications
of calcium chloride in the indicated quantities of water are given by
CaCl2(s) + 400 H;0(1) = CaCl2(400 H;0)
СаCla - 2 H:0(s) + 398 H:0(1) — СаCli:(400 H:0)
СаCli 4 H,0(8) + 396 H,0(1) — СаCl:(400 H,0)
CaCl2 • 6 H,0(s) + 394 H;0(1) = CaCla(400 H;O)
AH, = -17,990 cal
AH: = -10,030 cal
AH3 = -1830 cal
ΔΗ
%3D
+4560 cal
From these data find the heats of the following hydration reactions:
(a) CaCl2(s) + 2 H¿0(1) = CaCl2 · 2 H,0(s)
(b) СаCl; - 2 H0(8) + 2 H:0(1)
(c) CaCl, · 4 H20(s) + 2 H¿0(1) = CaCl, · 6 H,0(s)
(d) CaCl (s) + 6 H;0(1)
CaClą · 4 H20(s)
CaCl2 · 6 H,0(s)
Transcribed Image Text:23. The integral heats of solution at 18°C for the various solid modifications of calcium chloride in the indicated quantities of water are given by CaCl2(s) + 400 H;0(1) = CaCl2(400 H;0) СаCla - 2 H:0(s) + 398 H:0(1) — СаCli:(400 H:0) СаCli 4 H,0(8) + 396 H,0(1) — СаCl:(400 H,0) CaCl2 • 6 H,0(s) + 394 H;0(1) = CaCla(400 H;O) AH, = -17,990 cal AH: = -10,030 cal AH3 = -1830 cal ΔΗ %3D +4560 cal From these data find the heats of the following hydration reactions: (a) CaCl2(s) + 2 H¿0(1) = CaCl2 · 2 H,0(s) (b) СаCl; - 2 H0(8) + 2 H:0(1) (c) CaCl, · 4 H20(s) + 2 H¿0(1) = CaCl, · 6 H,0(s) (d) CaCl (s) + 6 H;0(1) CaClą · 4 H20(s) CaCl2 · 6 H,0(s)
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Thermodynamic Description of Mixtures
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY