23. In the reaction between copper(II) chloride and aluminum metal to form aluminum chloride and copper metal, what change in charge is observed? 3 Cucl, + 2 AI → 2 AICI, + 3 Cu a. copper decreases in charge from +1 to 0 b. aluminum decreases in charge from 0 to -3 c. aluminum increases in charge from 0 to +3 d. copper increases in charge from 0 to +2

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### Chemical Reaction and Charge Changes

**Topic: Redox Reactions**

#### Question:
In the reaction between copper(II) chloride and aluminum metal to form aluminum chloride and copper metal, what change in charge is observed?

#### Reaction Equation:
\[ 3 \text{CuCl}_2 + 2 \text{Al} \rightarrow 2 \text{AlCl}_3 + 3 \text{Cu} \]

#### Options:
a. Copper decreases in charge from +1 to 0  
b. Aluminum decreases in charge from 0 to -3  
c. Aluminum increases in charge from 0 to +3  
d. Copper increases in charge from 0 to +2  

#### Explanation:

In this redox reaction, let's analyze the oxidation states:

- **Copper (Cu):**
    - In \(\text{CuCl}_2\), copper is in the +2 oxidation state.
    - In the product form, copper is in its metallic state (Cu), which has an oxidation state of 0.
    - Thus, copper decreases in charge from +2 to 0.

- **Aluminum (Al):**
    - Aluminum starts in its elemental form with an oxidation state of 0.
    - In \(\text{AlCl}_3\), aluminum has an oxidation state of +3.
    - Thus, aluminum increases in charge from 0 to +3.

The correct option is:

**c. Aluminum increases in charge from 0 to +3**
Transcribed Image Text:### Chemical Reaction and Charge Changes **Topic: Redox Reactions** #### Question: In the reaction between copper(II) chloride and aluminum metal to form aluminum chloride and copper metal, what change in charge is observed? #### Reaction Equation: \[ 3 \text{CuCl}_2 + 2 \text{Al} \rightarrow 2 \text{AlCl}_3 + 3 \text{Cu} \] #### Options: a. Copper decreases in charge from +1 to 0 b. Aluminum decreases in charge from 0 to -3 c. Aluminum increases in charge from 0 to +3 d. Copper increases in charge from 0 to +2 #### Explanation: In this redox reaction, let's analyze the oxidation states: - **Copper (Cu):** - In \(\text{CuCl}_2\), copper is in the +2 oxidation state. - In the product form, copper is in its metallic state (Cu), which has an oxidation state of 0. - Thus, copper decreases in charge from +2 to 0. - **Aluminum (Al):** - Aluminum starts in its elemental form with an oxidation state of 0. - In \(\text{AlCl}_3\), aluminum has an oxidation state of +3. - Thus, aluminum increases in charge from 0 to +3. The correct option is: **c. Aluminum increases in charge from 0 to +3**
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