23. How much energy can be obtained from the roasting of 44.97 g of solid zinc sulfide given the following thermochemical equations ZnS) + /,0219) → ZnO(e) + SO29) (1) ZnO(s) → Zn(s) + ½O2(g) (2) S(s) + O29) → SO29) (3) ZnS(s) → Zn(s) + S(s) AH°, = +350.5 kJ AH°, = -296.8 kJ AH° = +206.0 kJ Show your work: Identify the law:
23. How much energy can be obtained from the roasting of 44.97 g of solid zinc sulfide given the following thermochemical equations ZnS) + /,0219) → ZnO(e) + SO29) (1) ZnO(s) → Zn(s) + ½O2(g) (2) S(s) + O29) → SO29) (3) ZnS(s) → Zn(s) + S(s) AH°, = +350.5 kJ AH°, = -296.8 kJ AH° = +206.0 kJ Show your work: Identify the law:
Chemistry
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![23. How much energy can be obtained from the roasting of 44.97 g of solid zinc sulfide given the following
thermochemical equations
ZnS) + 1,0219) → ZnOcs)
SO219)
+
(1) ZnO(s) → Zn(s) + ½O29)
(2) S(s) + O2(g) → SO29)
AH°, = +350.5 kJ
AH°, = -296.8 kJ
AH°, = +206.0 kJ
%3D
1
%3D
(3) ZnS(s) → Zn(s) + S(s)
Show your work:
Identify the law:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7ed257c7-1abb-4569-a5f6-7733c0232f0b%2F21672ce5-8d4d-49bb-a0da-138564e27ba1%2Flz3qap_processed.png&w=3840&q=75)
Transcribed Image Text:23. How much energy can be obtained from the roasting of 44.97 g of solid zinc sulfide given the following
thermochemical equations
ZnS) + 1,0219) → ZnOcs)
SO219)
+
(1) ZnO(s) → Zn(s) + ½O29)
(2) S(s) + O2(g) → SO29)
AH°, = +350.5 kJ
AH°, = -296.8 kJ
AH°, = +206.0 kJ
%3D
1
%3D
(3) ZnS(s) → Zn(s) + S(s)
Show your work:
Identify the law:
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