22. What type(s) of intermolecular forces are exhibited by the molecule below? VDW = van der Waals; DD = dipole-dipole; HB – hydrogen bonding (a) only VDW (b) VDW, DD, and HB (c) VDW and DD (d) only DD (e) VDW and HB

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**Intermolecular Forces in Molecules**

**Question:**

22. What type(s) of intermolecular forces are exhibited by the molecule below?
*VDW = van der Waals; DD = dipole-dipole; HB = hydrogen bonding*

[Diagram of molecule with three carbon atoms, six hydrogen atoms, and one oxygen atom arranged in a linear fashion, where the oxygen atom is bonded to two hydrogen atoms.]

- (a) only VDW
- (b) VDW, DD, and HB
- (c) VDW and DD
- (d) only DD
- (e) VDW and HB

*Explanation of Diagram:*

The diagram shows a molecule with the following structure:
- Three carbon atoms (C), in a chain, with hydrogens (H) attached to each carbon.
- An oxygen atom (O) is bonded to one of the carbons with two hydrogen atoms bonded to the oxygen, forming an OH (hydroxyl) group.

**Answer:**

To determine the intermolecular forces in this molecule, let's analyze its components:

- **Van der Waals (VDW) Forces**: These are weak forces that occur in all molecules due to temporary dipoles. Therefore, this molecule exhibits van der Waals forces.
  
- **Dipole-Dipole (DD) Interactions**: These occur when there are regions of positive and negative charge in different molecules that attract each other. In this molecule, the presence of the hydroxyl group (OH) means there are regions of partial positive and negative charges, indicating the presence of dipole-dipole interactions.
  
- **Hydrogen Bonding (HB)**: This is a specific type of dipole-dipole interaction that occurs when a hydrogen atom is bonded to a highly electronegative atom (like oxygen). The OH group in this molecule can form hydrogen bonds.

Thus, the molecule exhibits van der Waals forces, dipole-dipole interactions, and hydrogen bonding. The correct answer is:

- (b) VDW, DD, and HB
Transcribed Image Text:**Intermolecular Forces in Molecules** **Question:** 22. What type(s) of intermolecular forces are exhibited by the molecule below? *VDW = van der Waals; DD = dipole-dipole; HB = hydrogen bonding* [Diagram of molecule with three carbon atoms, six hydrogen atoms, and one oxygen atom arranged in a linear fashion, where the oxygen atom is bonded to two hydrogen atoms.] - (a) only VDW - (b) VDW, DD, and HB - (c) VDW and DD - (d) only DD - (e) VDW and HB *Explanation of Diagram:* The diagram shows a molecule with the following structure: - Three carbon atoms (C), in a chain, with hydrogens (H) attached to each carbon. - An oxygen atom (O) is bonded to one of the carbons with two hydrogen atoms bonded to the oxygen, forming an OH (hydroxyl) group. **Answer:** To determine the intermolecular forces in this molecule, let's analyze its components: - **Van der Waals (VDW) Forces**: These are weak forces that occur in all molecules due to temporary dipoles. Therefore, this molecule exhibits van der Waals forces. - **Dipole-Dipole (DD) Interactions**: These occur when there are regions of positive and negative charge in different molecules that attract each other. In this molecule, the presence of the hydroxyl group (OH) means there are regions of partial positive and negative charges, indicating the presence of dipole-dipole interactions. - **Hydrogen Bonding (HB)**: This is a specific type of dipole-dipole interaction that occurs when a hydrogen atom is bonded to a highly electronegative atom (like oxygen). The OH group in this molecule can form hydrogen bonds. Thus, the molecule exhibits van der Waals forces, dipole-dipole interactions, and hydrogen bonding. The correct answer is: - (b) VDW, DD, and HB
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