Methane (CH4) is a gas, but carbon tetrachloride (CC14) is a liquid at room temperature and standard pressure conditions. Which one of the following is the best explanation for this? The London dispersion forces in CH4 are stronger than the London dispersion forces in CCl4, so even though the two have the same bp, CCl4 is a liquid. O CCl4 is more polarizeable than CH4 and therefore has a higher bp. Cl is more electronegative than H, so the dipole-dipole forces in CCl4 are stronger than in CH4. CH4 exhibits hydrogen bonding, but CCl4 does not, therefore the bp of CCl4 is higher. O CCl4 is a polar molecule and CH4 is nonpolar, therefore CCl4 has a lower bp.

Methane (CH4) is a gas, but carbon tetrachloride (CC14) is a liquid at room temperature and standard pressure conditions. Which one of the following is the best explanation for this? The London dispersion forces in CH4 are stronger than the London dispersion forces in CCl4, so even though the two have the same bp, CCl4 is a liquid. O CCl4 is more polarizeable than CH4 and therefore has a higher bp. Cl is more electronegative than H, so the dipole-dipole forces in CCl4 are stronger than in CH4. CH4 exhibits hydrogen bonding, but CCl4 does not, therefore the bp of CCl4 is higher. O CCl4 is a polar molecule and CH4 is nonpolar, therefore CCl4 has a lower bp.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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