22. What is the mass in grams of each of the following? a. 3.011 × 10²⁹ atoms F b. 1.50 x 1023 atoms Mg c. 4.50 x 10¹2 atoms Cl d. 8.42 x 10¹8 atoms Br e. 25 atoms W f. 1 atom Au

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**Question 22: What is the mass in grams of each of the following?**

a. \(3.011 \times 10^{23}\) atoms F

b. \(1.50 \times 10^{23}\) atoms Mg

c. \(4.50 \times 10^{12}\) atoms Cl

d. \(8.42 \times 10^{18}\) atoms Br

e. 25 atoms W

f. 1 atom Au

---

To convert the number of atoms to grams, use the formula:

\[
\text{Mass (g)} = \left(\frac{\text{Number of Atoms}}{\text{Avogadro's Number}}\right) \times \text{Molar Mass (g/mol)}
\]

Where Avogadro's Number is \(6.022 \times 10^{23}\) atoms/mol. You will need the molar mass of each element:

- Fluorine (F): approximately 19 g/mol
- Magnesium (Mg): approximately 24.305 g/mol
- Chlorine (Cl): approximately 35.453 g/mol
- Bromine (Br): approximately 79.904 g/mol
- Tungsten (W): approximately 183.84 g/mol
- Gold (Au): approximately 196.967 g/mol

Calculate the mass for each part using the formula provided.
Transcribed Image Text:**Question 22: What is the mass in grams of each of the following?** a. \(3.011 \times 10^{23}\) atoms F b. \(1.50 \times 10^{23}\) atoms Mg c. \(4.50 \times 10^{12}\) atoms Cl d. \(8.42 \times 10^{18}\) atoms Br e. 25 atoms W f. 1 atom Au --- To convert the number of atoms to grams, use the formula: \[ \text{Mass (g)} = \left(\frac{\text{Number of Atoms}}{\text{Avogadro's Number}}\right) \times \text{Molar Mass (g/mol)} \] Where Avogadro's Number is \(6.022 \times 10^{23}\) atoms/mol. You will need the molar mass of each element: - Fluorine (F): approximately 19 g/mol - Magnesium (Mg): approximately 24.305 g/mol - Chlorine (Cl): approximately 35.453 g/mol - Bromine (Br): approximately 79.904 g/mol - Tungsten (W): approximately 183.84 g/mol - Gold (Au): approximately 196.967 g/mol Calculate the mass for each part using the formula provided.
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