22. Methanol, CH3OH (32.04 g/mol) has a melting point equal to 176 K and a boiling point equal to 338 K. Using thethermodynamic data below, calculate the amount of heat (kJ) required to convert 0.484 mol CH3OH from 115 Kto 200 K.(15.51) (1) (mm) (3)2.08AHfusion = 2.2 kJ/molAHvaporization = 35.2 kJ/molA. 5.11 kJChloroformAcetoneTemperatureA. 162.9 torrB. 27.9 kJMolar Mass (g/mol) Density (g/mL)119.3858.0823. What is the total vapor pressure of a solution prepared by mixing 75.0 mL chloroform with 100.0 mL acetone. Atthe same temperature, their vapor pressures are 154.8 torr and 184.5 torr, respectively.A. 22.8 mLCsolid 105 J/mol-KCliquid = 81.3 J/mol-KCgas 48 J/mol-KB. 172.4 torr1C. 74.2 kJ1.480.786Vapor Pressure (torr)154.8184.5C. 180.1 torr+484) (351)176-115 =C. 43.3 mL24. How many milliliters of ethanol (CH3CH₂OH, density = 0.791 g/mL, 32.04 g/mol) are required to prepare a2.70 M solution with a total volume of 500.0 mL?1200D. 131 kJ 10648= 124B. 30.4 mLD. 54.7 mL25. Choose the best answer to describe what is taking place in dotted square portion of the graph below.FNEHeatA. A gas is cooled and partially condensed to a liquid.CB. A gas is cooled and completely condensed to a liquid.C. A gas is cooled, completely condensed, and the liquid is cooled.D. A liquid is cooled and completed frozen to a solid.6 faces& corned16 edgesD. 393.6 torr4 + 182.34347.42 WIJ PCFE12/244fo847C17VEC3

Answered: Image /qna-images/answer/c2e02e9d-e157-4b10-86a6-861a1059031f.jpg

22. Methanol, CH3OH (32.04 g/mol) has a melting point equal to 176 K and a boiling point equal to 338 K. Using the thermodynamic data below, calculate the amount of heat (kJ) required to convert 0.484 mol CH3OH from 115 K to 200 K. (15.51) (1) (mm) (3 2,08 AHfusion = 2.2 kJ/mol AHvaporization = 35.2 kJ/mol A. 5.11 kJ 1 B. 27.9 kJ Csolid 105 J/mol-K Cliquid = 81.3 J/mol-K Cgas 48 J/mol-K = C. 74.2 kJ (1484) (351) 176-115 = D. 131 kJ ich 100.0 = 124 gostong At 17

22. Methanol, CH3OH (32.04 g/mol) has a melting point equal to 176 K and a boiling point equal to 338 K. Using the thermodynamic data below, calculate the amount of heat (kJ) required to convert 0.484 mol CH3OH from 115 K to 200 K. (15.51) (1) (mm) (3 2,08 AHfusion = 2.2 kJ/mol AHvaporization = 35.2 kJ/mol A. 5.11 kJ 1 B. 27.9 kJ Csolid 105 J/mol-K Cliquid = 81.3 J/mol-K Cgas 48 J/mol-K = C. 74.2 kJ (1484) (351) 176-115 = D. 131 kJ ich 100.0 = 124 gostong At 17

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Thermochemistry

Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.

Exergonic Reaction

The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.

Question

22. Methanol, CH3OH (32.04 g/mol) has a melting point equal to 176 K and a boiling point equal to 338 K. Using the
thermodynamic data below, calculate the amount of heat (kJ) required to convert 0.484 mol CH3OH from 115 K
to 200 K.
(15.51) (1) (mm) (3)
2.08
AHfusion = 2.2 kJ/mol
AHvaporization = 35.2 kJ/mol
A. 5.11 kJ
Chloroform
Acetone
Temperature
A. 162.9 torr
B. 27.9 kJ
Molar Mass (g/mol) Density (g/mL)
119.38
58.08
23. What is the total vapor pressure of a solution prepared by mixing 75.0 mL chloroform with 100.0 mL acetone. At
the same temperature, their vapor pressures are 154.8 torr and 184.5 torr, respectively.
A. 22.8 mL
Csolid 105 J/mol-K
Cliquid = 81.3 J/mol-K
Cgas 48 J/mol-K
B. 172.4 torr
1
C. 74.2 kJ
1.48
0.786
Vapor Pressure (torr)
154.8
184.5
C. 180.1 torr
+484) (351)
176-115 =
C. 43.3 mL
24. How many milliliters of ethanol (CH3CH₂OH, density = 0.791 g/mL, 32.04 g/mol) are required to prepare a
2.70 M solution with a total volume of 500.0 mL?
1
200
D. 131 kJ 10648
= 124
B. 30.4 mL
D. 54.7 mL
25. Choose the best answer to describe what is taking place in dotted square portion of the graph below.
FNE
Heat
A. A gas is cooled and partially condensed to a liquid.
CB. A gas is cooled and completely condensed to a liquid.
C. A gas is cooled, completely condensed, and the liquid is cooled.
D. A liquid is cooled and completed frozen to a solid.
6 faces
& corned
16 edges
D. 393.6 torr
4 + 1
82.34
347.4
2 WIJ P
CFE
12/2
4
4
fo
8
47
C
17
VE
C
3

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