24VC₁=1000µFC₂=500pFC₁=1500μFC₂-5100µFC₁=1500μFC₂=1000μFC₁=100μFC₁=1300μF 22.23.24.25.Qeq = ?a. 158 mCb. 158 μCV1234 = ?a. 79/4 Vb. 396/49 VV67=?a. 119/1560 Vb. 1560/119Q6=?Va. 507/125 mCb. 833/250 μCc. 396/49 mCd. 396/49 μCc. 49/396 Vd. 13689/539 Vc. 237/14 Vd. 553/48 Vc. 833/1014 mCd. 1014/833 µC

In this question, We need to determine the charge and voltage across the different different…

22. 23. 24. 25. Qeq = ? a. 158 mC b. 158 μC V1234 = ? a. 79/4 V b. 396/49 V V67=? a. 119/1560 V b. 1560/119 V Q6=? a. 507/125 mC b. 833/250 μC c. 396/49 mC d. 396/49 μC c. 49/396 V d. 13689/539 V c. 237/14 V d. 553/48 V c. 833/1014 mC d. 1014/833 µC

22. 23. 24. 25. Qeq = ? a. 158 mC b. 158 μC V1234 = ? a. 79/4 V b. 396/49 V V67=? a. 119/1560 V b. 1560/119 V Q6=? a. 507/125 mC b. 833/250 μC c. 396/49 mC d. 396/49 μC c. 49/396 V d. 13689/539 V c. 237/14 V d. 553/48 V c. 833/1014 mC d. 1014/833 µC

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

24V
C₁=1000µF
C₂=500pF
C₁=1500μF
C₂-5100µF
C₁=1500μF
C₂=1000μF
C₁=100μF
C₁=1300μF

22.
23.
24.
25.
Qeq = ?
a. 158 mC
b. 158 μC
V1234 = ?
a. 79/4 V
b. 396/49 V
V67=?
a. 119/1560 V
b. 1560/119
Q6=?
V
a. 507/125 mC
b. 833/250 μC
c. 396/49 mC
d. 396/49 μC
c. 49/396 V
d. 13689/539 V
c. 237/14 V
d. 553/48 V
c. 833/1014 mC
d. 1014/833 µC

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