(c) The diodes in the circuit are biaced and identical. Each represented by the exponential model, I = Is e V/V+, the diode and with the diagram marked to help you get started, value of find the R such it is that I₂ = 10mA- Va= V₁ + 50mV 50 mV R 10 MA 50 mV. + . where I is the current through. V is the voltage across it. the voltage drop across I₁ = 50mV R bath + Forward- diode can be 50mV DI 50 mV

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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(c)
The diodes in the circuit are
biaced and
Each
represented by the
exponential model
I = Is e V/V+, where I is the current through.
V is the voltage across it.
the diode
and
with the diagram marked to help you get
value of
started,
find
the
R
the vreltage drap
across
such
it is
that
50 mV.
10 MA
Va= V₁ + 50mV
Ia = 10mA - 50 mV
R
identical.
+
Da
.
I₁ =
50mV
R
↓
50mV
R
R
ó
bath
forward-
divde
50mV
can be
Transcribed Image Text:(c) The diodes in the circuit are biaced and Each represented by the exponential model I = Is e V/V+, where I is the current through. V is the voltage across it. the diode and with the diagram marked to help you get value of started, find the R the vreltage drap across such it is that 50 mV. 10 MA Va= V₁ + 50mV Ia = 10mA - 50 mV R identical. + Da . I₁ = 50mV R ↓ 50mV R R ó bath forward- divde 50mV can be
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