*22 A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector 7 = (2.00 m)i – (3.00 m)j + (2.00 m)k, the force is given by F = Fi + (7.00 N)j – (6.00 N)k and the corresponding torque about the origin is 7 = (4.00 N m)i + (2.00 N m)j – (1.00N m)k. Determine F..

*22 A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector 7 = (2.00 m)i – (3.00 m)j + (2.00 m)k, the force is given by F = Fi + (7.00 N)j – (6.00 N)k and the corresponding torque about the origin is 7 = (4.00 N m)i + (2.00 N m)j – (1.00N m)k. Determine F..

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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