Ionic Equilibrium
Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.
Arrhenius Acid
Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.
Bronsted Lowry Base In Inorganic Chemistry
Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.
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### Question 21: Identify the Lewis Acid in the Reaction.
The given chemical reaction involves the following components:
- Reactant 1: \( \text{SO}_3 \)
- Reactant 2: \( [ \text{O} ]^{2-} \)
The reaction yields:
- Product: \( \left[ \text{SO}_4 \right]^{2-} \)
The task is to identify the Lewis acid in this reaction.
##### Multiple-Choice Options:
- A) \( \text{SO}_3 \)
- B) \( [ \text{O} ]^{2-} \)
- C) \( \left[ \text{SO}_4 \right]^{2-} \)
- D) None of these.
- E) All of these.
**Explanation:**
- **Reactants and Products:**
- \( \text{SO}_3 \) (Sulfur trioxide) is a molecule with sulfur atom double-bonded to three oxygen atoms.
- \( [ \text{O} ]^{2-} \) represents a doubly negatively charged oxygen ion.
- The reaction yields \( \left[ \text{SO}_4 \right]^{2-} \), a sulfate ion where sulfur is central and bonded to four oxygen atoms, one of which forms a coordinate bond.
- **Concept of Lewis Acids and Bases:**
- **Lewis Acid**: A compound or ionic species that can accept an electron pair.
- **Lewis Base**: A compound or ionic species that can donate an electron pair.
In the given reaction:
- \( \text{SO}_3 \) acts as the **Lewis acid** because it accepts an electron pair from the \( [ \text{O} ]^{2-} \) ion.
- \( [ \text{O} ]^{2-} \) acts as the **Lewis base** because it donates an electron pair to \( \text{SO}_3 \).
Hence, the correct answer is:
- **A) \( \text{SO}_3 \)**
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