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206Pbfor A rock contains 0.688 mg of every 1.000 mg of 238 Upresent. Assuming that no lead was originally present, that all the 206Pb formed over the years has remained in the rock, and that the number of nuclides in intermediate stages of decay between 238 U and 206Pb is negligible, calculate the age of the rock. (For 238 U, t1/2 = 4.5 × 10⁹ years.)

206Pbfor A rock contains 0.688 mg of every 1.000 mg of 238 Upresent. Assuming that no lead was originally present, that all the 206Pb formed over the years has remained in the rock, and that the number of nuclides in intermediate stages of decay between 238 U and 206Pb is negligible, calculate the age of the rock. (For 238 U, t1/2 = 4.5 × 10⁹ years.)

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Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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A rock contains 0.688 mg of 206Pbfor every 1.000 mg of 238 Upresent. Assuming that no lead was originally present, that all the 206 Pb formed over the years has remained in the rock, and that the number of nuclides in intermediate stages of decay between 238 U and 206 Pb is negligible, calculate the age of the rock. (For 238 U, t1/2 = 4.5 × 10⁹ 4.5 × 10⁹ years.)
Transcribed Image Text:A rock contains 0.688 mg of 206Pbfor every 1.000 mg of 238 Upresent. Assuming that no lead was originally present, that all the 206 Pb formed over the years has remained in the rock, and that the number of nuclides in intermediate stages of decay between 238 U and 206 Pb is negligible, calculate the age of the rock. (For 238 U, t1/2 = 4.5 × 10⁹ 4.5 × 10⁹ years.)
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