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2023 22² 26.57 a 12-1-21 4-91=0 In wwwwww - wwwwww In -www- + + 4=91 + 121 1 IOV 8V H Bur www. Port Aneeds me to find the potential of port a with respect to ponto in us figure EV=O 21 -I-8-21-I =O I = g A V₂ - Vb M wwww. in = 2-4I no current sportch is open 4 I-2 16+21 +1 -12 + I + 3 (0) +10 +1(0) = √6 Va-V=-41 +2 Vo = 22 V if Part B wants me to find the magnitude of the current in the 12 V battery ponts a and b are connected by a wire. 0.444 A Vab=2-4(0.444A)

2023 22² 26.57 a 12-1-21 4-91=0 In wwwwww - wwwwww In -www- + + 4=91 + 121 1 IOV 8V H Bur www. Port Aneeds me to find the potential of port a with respect to ponto in us figure EV=O 21 -I-8-21-I =O I = g A V₂ - Vb M wwww. in = 2-4I no current sportch is open 4 I-2 16+21 +1 -12 + I + 3 (0) +10 +1(0) = √6 Va-V=-41 +2 Vo = 22 V if Part B wants me to find the magnitude of the current in the 12 V battery ponts a and b are connected by a wire. 0.444 A Vab=2-4(0.444A)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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**Transcription of Circuit Analysis Notes** --- **Diagram Explanation:** The diagram depicts a complex electrical circuit. Key components include: - Several resistors with values denoted as \(1 \Omega\), \(3 \Omega\), and \(2 \Omega\). - Three voltage sources: \(12V\), \(10V\), and \(8V\). - Points labeled as \(a\) and \(b\) for reference. - Note indicating "no current switch is open", suggesting an open circuit path on the right side. --- **Handwritten Notes:** **26.57** - **Objective:** Part A requires finding the potential of point \(a\) with respect to point \(b\) in the figure. \[ \sum V = 0 \] **Equation Setup:** 1. \(12 - I - 2I - 1 - I - 3 - 2I - I = 0\) Simplified: \[ 4 - 9I = 0 \quad \text{or} \quad 4 = 9I \quad \Rightarrow \quad I = \frac{4}{9} \, \text{A} \approx 0.444 \, \text{A} \] 2. \(4I = 2 + 1 + 3 + 10 + (1) - V_6 = V_6\) - **Equations:** \[ V_a - V_b = 2 - 4I \] \[ V_{ab} = 2 - 4(0.444) \] \[ V_{ab} = 2.2V \] --- **Part B:** - Requires finding the magnitude of the current in the 12V battery if points \(c\) and \(b\) are connected by a wire. --- End of transcription.
Transcribed Image Text:**Transcription of Circuit Analysis Notes** --- **Diagram Explanation:** The diagram depicts a complex electrical circuit. Key components include: - Several resistors with values denoted as \(1 \Omega\), \(3 \Omega\), and \(2 \Omega\). - Three voltage sources: \(12V\), \(10V\), and \(8V\). - Points labeled as \(a\) and \(b\) for reference. - Note indicating "no current switch is open", suggesting an open circuit path on the right side. --- **Handwritten Notes:** **26.57** - **Objective:** Part A requires finding the potential of point \(a\) with respect to point \(b\) in the figure. \[ \sum V = 0 \] **Equation Setup:** 1. \(12 - I - 2I - 1 - I - 3 - 2I - I = 0\) Simplified: \[ 4 - 9I = 0 \quad \text{or} \quad 4 = 9I \quad \Rightarrow \quad I = \frac{4}{9} \, \text{A} \approx 0.444 \, \text{A} \] 2. \(4I = 2 + 1 + 3 + 10 + (1) - V_6 = V_6\) - **Equations:** \[ V_a - V_b = 2 - 4I \] \[ V_{ab} = 2 - 4(0.444) \] \[ V_{ab} = 2.2V \] --- **Part B:** - Requires finding the magnitude of the current in the 12V battery if points \(c\) and \(b\) are connected by a wire. --- End of transcription.
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