2023 22² 26.57 a 12-1-21 4-91=0 In wwwwww - wwwwww In -www- + + 4=91 + 121 1 IOV 8V H Bur www. Port Aneeds me to find the potential of port a with respect to ponto in us figure EV=O 21 -I-8-21-I =O I = g A V₂ - Vb M wwww. in = 2-4I no current sportch is open 4 I-2 16+21 +1 -12 + I + 3 (0) +10 +1(0) = √6 Va-V=-41 +2 Vo = 22 V if Part B wants me to find the magnitude of the current in the 12 V battery ponts a and b are connected by a wire. 0.444 A Vab=2-4(0.444A)
2023 22² 26.57 a 12-1-21 4-91=0 In wwwwww - wwwwww In -www- + + 4=91 + 121 1 IOV 8V H Bur www. Port Aneeds me to find the potential of port a with respect to ponto in us figure EV=O 21 -I-8-21-I =O I = g A V₂ - Vb M wwww. in = 2-4I no current sportch is open 4 I-2 16+21 +1 -12 + I + 3 (0) +10 +1(0) = √6 Va-V=-41 +2 Vo = 22 V if Part B wants me to find the magnitude of the current in the 12 V battery ponts a and b are connected by a wire. 0.444 A Vab=2-4(0.444A)
Chapter4: Symbols
Section: Chapter Questions
Problem 3SQ: What do the following abbreviations stand for? a. SPST b. SPDT c. DPST d. DPDT e. NO f. NC
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Question
![**Transcription of Circuit Analysis Notes**
---
**Diagram Explanation:**
The diagram depicts a complex electrical circuit. Key components include:
- Several resistors with values denoted as \(1 \Omega\), \(3 \Omega\), and \(2 \Omega\).
- Three voltage sources: \(12V\), \(10V\), and \(8V\).
- Points labeled as \(a\) and \(b\) for reference.
- Note indicating "no current switch is open", suggesting an open circuit path on the right side.
---
**Handwritten Notes:**
**26.57**
- **Objective:** Part A requires finding the potential of point \(a\) with respect to point \(b\) in the figure.
\[
\sum V = 0
\]
**Equation Setup:**
1. \(12 - I - 2I - 1 - I - 3 - 2I - I = 0\)
Simplified:
\[
4 - 9I = 0 \quad \text{or} \quad 4 = 9I \quad \Rightarrow \quad I = \frac{4}{9} \, \text{A} \approx 0.444 \, \text{A}
\]
2. \(4I = 2 + 1 + 3 + 10 + (1) - V_6 = V_6\)
- **Equations:**
\[
V_a - V_b = 2 - 4I
\]
\[
V_{ab} = 2 - 4(0.444)
\]
\[
V_{ab} = 2.2V
\]
---
**Part B:**
- Requires finding the magnitude of the current in the 12V battery if points \(c\) and \(b\) are connected by a wire.
---
End of transcription.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdcf1461b-3cc5-4096-be3f-6b26fd0aaa3e%2F851d6bed-a5e2-45a2-bd18-efb5ac44245e%2F8p5zzf5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Transcription of Circuit Analysis Notes**
---
**Diagram Explanation:**
The diagram depicts a complex electrical circuit. Key components include:
- Several resistors with values denoted as \(1 \Omega\), \(3 \Omega\), and \(2 \Omega\).
- Three voltage sources: \(12V\), \(10V\), and \(8V\).
- Points labeled as \(a\) and \(b\) for reference.
- Note indicating "no current switch is open", suggesting an open circuit path on the right side.
---
**Handwritten Notes:**
**26.57**
- **Objective:** Part A requires finding the potential of point \(a\) with respect to point \(b\) in the figure.
\[
\sum V = 0
\]
**Equation Setup:**
1. \(12 - I - 2I - 1 - I - 3 - 2I - I = 0\)
Simplified:
\[
4 - 9I = 0 \quad \text{or} \quad 4 = 9I \quad \Rightarrow \quad I = \frac{4}{9} \, \text{A} \approx 0.444 \, \text{A}
\]
2. \(4I = 2 + 1 + 3 + 10 + (1) - V_6 = V_6\)
- **Equations:**
\[
V_a - V_b = 2 - 4I
\]
\[
V_{ab} = 2 - 4(0.444)
\]
\[
V_{ab} = 2.2V
\]
---
**Part B:**
- Requires finding the magnitude of the current in the 12V battery if points \(c\) and \(b\) are connected by a wire.
---
End of transcription.
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Step 1: Determination of given parameters,
The circuit diagram,
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