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2020 sample 2019 sample 350 N (population size) n (sample sire) X (sample mean) a (population standard deviation) s (Sample standard deviation) 500 25 25 45 55 12 15 18 20 (a) Test at the 5% significance level that the null hypothesis that the population mean score for 2020 is greater than or equal to 60 against the alternative that it is less than 60 for the following two cases. Case 1: Population standard deviation is known to be 12. Case 2 Population standard deviation is unknown. Sample standard deviation is computed as 18. Include null and altermative hypotheses, decision rules and your decisions. Interpret your result. (b) Test at the 5% significance level that the difference between the mean exam scores from two years (sct it as H2020 - H2019| is 5 against the alternative that it is not 5, given independent sample with unknown population variance with no equality assumption. Use v = 40. Interpret your result. (c) Compute p-value for part (b). Interpret your result. (d) Compute Type Il error probability for part (b) by assuming the population difference under H1 is 18. Interpret your result. Twe tail test (lwer tasi case f d- 0) t-values 0.025 2.021 0.1 0.01 2.423 0.05 0.005 40 1303 1.684 2.704 This is a basic form. Adjust if necessary. Z-values F(z) 0,90 0.95 0.975 0.99 0,995

2020 sample 2019 sample 350 N (population size) n (sample sire) X (sample mean) a (population standard deviation) s (Sample standard deviation) 500 25 25 45 55 12 15 18 20 (a) Test at the 5% significance level that the null hypothesis that the population mean score for 2020 is greater than or equal to 60 against the alternative that it is less than 60 for the following two cases. Case 1: Population standard deviation is known to be 12. Case 2 Population standard deviation is unknown. Sample standard deviation is computed as 18. Include null and altermative hypotheses, decision rules and your decisions. Interpret your result. (b) Test at the 5% significance level that the difference between the mean exam scores from two years (sct it as H2020 - H2019| is 5 against the alternative that it is not 5, given independent sample with unknown population variance with no equality assumption. Use v = 40. Interpret your result. (c) Compute p-value for part (b). Interpret your result. (d) Compute Type Il error probability for part (b) by assuming the population difference under H1 is 18. Interpret your result. Twe tail test (lwer tasi case f d- 0) t-values 0.025 2.021 0.1 0.01 2.423 0.05 0.005 40 1303 1.684 2.704 This is a basic form. Adjust if necessary. Z-values F(z) 0,90 0.95 0.975 0.99 0,995

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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2020 sarmple 2019 sample N (population size) n (sample size) X (sample mean) a (population standard deviation) s (Sample standard deviation) 500 350 25 25 55 45 12 15 18 20 (a) Test at the 5% significance level that the null hypothesis that the population mean score for 2020 is greater than or equal to 60 against the alternative that it is less than 60 for the following two cases. Case 1: Population standard deviation is known to be 12. Case 2 Population standard deviation is unknown. Sample standard deviation is computed as 18. Include null und alternative hypotheses, decision rules and your decisions. Interpret your result. (b) Test at the 5% significance level that the difference between the mean exam scores from two years (sct it as H2020 – H2019| is 5 against the alternative that it is not 5, given independent sample with unknown population variance with no equality assumption. Use v = 40. Interpret your result. (c) Compute p-value for part (b). Interpret your result. (d) Compute Type Il error probability for part (b) by assuming the population difference under H1 is 18. Interpret your result. Twe tail test (tower tasi case if d- D <o): t-values 0.1 0.05 0,025 0.01 0.005 40 1.303 1.684 2.021 2.423 2.704 Z-values This is a basic form. Adjust if necessary. F() 0.90 0.95 1.64 0.975 0.99 0,995 2.57 1.28 1.96 2.33
Transcribed Image Text:2020 sarmple 2019 sample N (population size) n (sample size) X (sample mean) a (population standard deviation) s (Sample standard deviation) 500 350 25 25 55 45 12 15 18 20 (a) Test at the 5% significance level that the null hypothesis that the population mean score for 2020 is greater than or equal to 60 against the alternative that it is less than 60 for the following two cases. Case 1: Population standard deviation is known to be 12. Case 2 Population standard deviation is unknown. Sample standard deviation is computed as 18. Include null und alternative hypotheses, decision rules and your decisions. Interpret your result. (b) Test at the 5% significance level that the difference between the mean exam scores from two years (sct it as H2020 – H2019| is 5 against the alternative that it is not 5, given independent sample with unknown population variance with no equality assumption. Use v = 40. Interpret your result. (c) Compute p-value for part (b). Interpret your result. (d) Compute Type Il error probability for part (b) by assuming the population difference under H1 is 18. Interpret your result. Twe tail test (tower tasi case if d- D <o): t-values 0.1 0.05 0,025 0.01 0.005 40 1.303 1.684 2.021 2.423 2.704 Z-values This is a basic form. Adjust if necessary. F() 0.90 0.95 1.64 0.975 0.99 0,995 2.57 1.28 1.96 2.33
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