20.A cylindrical resistance heater is placed horizontally in air. The outer surface temperature of the resistance wire is to be determined. The environment temperature Tair = 80.0°C and the power heater is 350.0w The length and the diameter of the resistance heater is 0.75 m and 0.5 cm. 白 Air Resistance heater, T, (D=0.5 cm L= 0.75 m properties of air at 1atm The 500°C are: 015890 || 1 v = 7.804 x 10 °m -s-1 Pr = 0.6986 B = 0.001294K %3D -1 安苏白 50E106 50E106
20.A cylindrical resistance heater is placed horizontally in air. The outer surface temperature of the resistance wire is to be determined. The environment temperature Tair = 80.0°C and the power heater is 350.0w The length and the diameter of the resistance heater is 0.75 m and 0.5 cm. 白 Air Resistance heater, T, (D=0.5 cm L= 0.75 m properties of air at 1atm The 500°C are: 015890 || 1 v = 7.804 x 10 °m -s-1 Pr = 0.6986 B = 0.001294K %3D -1 安苏白 50E106 50E106
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
Transcribed Image Text:20.A cylindrical resistance heater is placed
horizontally in air. The outer surface temperature
of the resistance wire is to be determined.
The environment temperature Tair = 80.0°C
heater is 350.ow
The length and the diameter of the resistance
heater is 0.75 m and 0.5 cm.
Air
Resistance
heater, T,
[D=0.5 cm
L = 0.75 m
The properties of air at 1atm
0158502
k = 0.05572W - m
%3D
-1
K
1
v = 7.804 x 10°m - s-1
Pr = 0.6986
B= 0.001294K
安が
-1
安苏白
91915850E106
91915850E106
Hint:
Transcribed Image Text:Start your guess from 1 2U C106
Pr = 0.698606
L= 0.75 m
The properties of air at 1atm and 500°C are:
k = 0.05572W - m-1. K
-1
v = 7.804 x 10°m -s-1
|
安苏白
3 =
0.001294K 1
%3D
91915850E106
Hint:
苏白
o苏白
Nu =| 0.6 +
0.387RA
%3D
1+
0599
/Pr
Iterate at least for 2 times.
安苏白
91915850E106
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