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20. Using the data provided, solve for the enthalpy change value of the target equation. Note: Include all rough notes, show all calculations, follow the rules of significant figures, and box your final answer. (1) C₂H5OH(1) + 30₂(g) → 2CO₂ + 3H₂O(1) (2) C(s) + O₂(g) → CO₂(g) (3) 2H₂(g) + O₂(g) → 2H₂O(l) (Target) 4C(s) + 6H₂(g) + O₂(g) → 2C₂H5OH(1) AH = -1367 kJ AH = -394 kJ AH = -572 kJ ΔΗ= ?

20. Using the data provided, solve for the enthalpy change value of the target equation. Note: Include all rough notes, show all calculations, follow the rules of significant figures, and box your final answer. (1) C₂H5OH(1) + 30₂(g) → 2CO₂ + 3H₂O(1) (2) C(s) + O₂(g) → CO₂(g) (3) 2H₂(g) + O₂(g) → 2H₂O(l) (Target) 4C(s) + 6H₂(g) + O₂(g) → 2C₂H5OH(1) AH = -1367 kJ AH = -394 kJ AH = -572 kJ ΔΗ= ?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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20. Using the data provided, solve for the enthalpy change value of the target equation. Note: Include all rough notes, show all calculations, follow the rules of significant figures, and box your final answer. (1) C₂H5OH(I) + 30₂(g) → 2CO₂ + 3H₂O(1) (2) C(s) + O₂(g) → CO₂(g) (3) 2H₂(g) + O₂(g) → 2H₂O(1) (Target) 4C(s) + 6H₂(g) + O₂(g) → 2C₂H5OH(1) AH° -1367 kJ AH = -394 kJ AH = -572 kJ ΔΗ = ?
Transcribed Image Text:20. Using the data provided, solve for the enthalpy change value of the target equation. Note: Include all rough notes, show all calculations, follow the rules of significant figures, and box your final answer. (1) C₂H5OH(I) + 30₂(g) → 2CO₂ + 3H₂O(1) (2) C(s) + O₂(g) → CO₂(g) (3) 2H₂(g) + O₂(g) → 2H₂O(1) (Target) 4C(s) + 6H₂(g) + O₂(g) → 2C₂H5OH(1) AH° -1367 kJ AH = -394 kJ AH = -572 kJ ΔΗ = ?
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