**Problem 20: Work-Energy Theorem Application**Use the work-energy theorem to find the force required to accelerate an electron (mass \( m = 9.11 \times 10^{-31} \) kg) moving along the x-axis from \( 4.00 \times 10^6 \) m/s to \( 1.60 \times 10^7 \) m/s over a distance of 0.0125 m.**Options:**A) \( 8.75 \times 10^{-15} \) N B) \( 5.47 \times 10^{-22} \) N C) \( 8.20 \times 10^{-17} \) N D) \( 1.64 \times 10^{-14} \) N E) \( 3.56 \times 10^{-19} \) N **Explanation:**This problem is designed to apply the work-energy theorem, which states that the work done on an object is equal to its change in kinetic energy. Given the mass of the electron and both its initial and final velocities, along with the distance over which this change occurs, you can determine the force required using this principle.

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Description: **Problem 20: Work-Energy Theorem Application**Use the work-energy theorem to find the force required to accelerate an electron (mass \( m = 9.11 \times 10^{-31} \) kg) moving along the x-axis from \( 4.00 \times 10^6 \) m/s to \( 1.60 \times 10^7 \

Given that: m=9.11×10-31 kgu=4.0×106 m/sv=1.6×107 m/sd=0.0125 mF=?

Answered: 20. Use the work-energy theorem to find…

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20. Use the work-energy theorem to find the force required to accelerate an electron (m= 9.11 x 10-31 kg) moving along the x axis from 4.00 x 106 m/s to 1.60 x 107 m/s in a distance of 0.0125 m.

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Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

**Problem 20: Work-Energy Theorem Application**

Use the work-energy theorem to find the force required to accelerate an electron (mass \( m = 9.11 \times 10^{-31} \) kg) moving along the x-axis from \( 4.00 \times 10^6 \) m/s to \( 1.60 \times 10^7 \) m/s over a distance of 0.0125 m.

**Options:**

A) \( 8.75 \times 10^{-15} \) N
B) \( 5.47 \times 10^{-22} \) N
C) \( 8.20 \times 10^{-17} \) N
D) \( 1.64 \times 10^{-14} \) N
E) \( 3.56 \times 10^{-19} \) N

**Explanation:**

This problem is designed to apply the work-energy theorem, which states that the work done on an object is equal to its change in kinetic energy. Given the mass of the electron and both its initial and final velocities, along with the distance over which this change occurs, you can determine the force required using this principle.

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