20. A hockey puck with mass 0.20 kg is traveling north with a speed of 15 m/s. A Dallas Star forward hits the puck with his hockey stick and after being hit the puck is traveling south with a speed of 25 m/s. What is the magnitude of the impulse that the stick applied to the puck?
20. A hockey puck with mass 0.20 kg is traveling north with a speed of 15 m/s. A Dallas Star forward hits the puck with his hockey stick and after being hit the puck is traveling south with a speed of 25 m/s. What is the magnitude of the impulse that the stick applied to the puck?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Physics Problem: Calculating Impulse Applied to a Hockey Puck
**Problem Statement:**
A hockey puck with a mass of 0.20 kg is traveling north with a speed of 15 m/s. A Dallas Star forward hits the puck with his hockey stick and, after being hit, the puck is traveling south with a speed of 25 m/s.
**Question:**
What is the magnitude of the impulse that the stick applied to the puck?
**Solution:**
When solving this problem, remember that impulse is defined as the change in momentum (Δp), and it can be calculated using the formula:
\[ \vec{J} = \Delta \vec{p} = m \cdot \Delta \vec{v} \]
where:
- \(\vec{J}\) is the impulse,
- \(m\) is the mass of the puck,
- \(\Delta \vec{v}\) is the change in velocity.
First, we need to determine the change in velocity:
1. Before being hit, the puck is traveling north with a velocity of \(15 \, m/s \).
2. After being hit, the puck is traveling south with a velocity of \(25 \, m/s \).
For the purpose of calculation, let’s consider the north direction as positive and the south direction as negative. Thus:
- Initial velocity (\(v_i\)) = \(+15 \, m/s\)
- Final velocity (\(v_f\)) = \(-25 \, m/s\)
The change in velocity (\(\Delta \vec{v}\)) is:
\[ \Delta \vec{v} = v_f - v_i \]
\[ \Delta \vec{v} = -25 \, m/s - (+15 \, m/s) \]
\[ \Delta \vec{v} = -25 \, m/s - 15 \, m/s \]
\[ \Delta \vec{v} = -40 \, m/s \]
Now, we use the mass of the puck (0.20 kg) to calculate the impulse:
\[ \vec{J} = m \cdot \Delta \vec{v} \]
\[ \vec{J} = 0.20 \, kg \cdot -40 \, m/s \]
\[ \vec{J} = -8.0 \, kg \cdot m/s \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6a5d5111-1d2a-4970-848c-d397a90063e1%2F75c3a520-1883-4b63-8275-4f91a6afd13a%2F3483z1j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Physics Problem: Calculating Impulse Applied to a Hockey Puck
**Problem Statement:**
A hockey puck with a mass of 0.20 kg is traveling north with a speed of 15 m/s. A Dallas Star forward hits the puck with his hockey stick and, after being hit, the puck is traveling south with a speed of 25 m/s.
**Question:**
What is the magnitude of the impulse that the stick applied to the puck?
**Solution:**
When solving this problem, remember that impulse is defined as the change in momentum (Δp), and it can be calculated using the formula:
\[ \vec{J} = \Delta \vec{p} = m \cdot \Delta \vec{v} \]
where:
- \(\vec{J}\) is the impulse,
- \(m\) is the mass of the puck,
- \(\Delta \vec{v}\) is the change in velocity.
First, we need to determine the change in velocity:
1. Before being hit, the puck is traveling north with a velocity of \(15 \, m/s \).
2. After being hit, the puck is traveling south with a velocity of \(25 \, m/s \).
For the purpose of calculation, let’s consider the north direction as positive and the south direction as negative. Thus:
- Initial velocity (\(v_i\)) = \(+15 \, m/s\)
- Final velocity (\(v_f\)) = \(-25 \, m/s\)
The change in velocity (\(\Delta \vec{v}\)) is:
\[ \Delta \vec{v} = v_f - v_i \]
\[ \Delta \vec{v} = -25 \, m/s - (+15 \, m/s) \]
\[ \Delta \vec{v} = -25 \, m/s - 15 \, m/s \]
\[ \Delta \vec{v} = -40 \, m/s \]
Now, we use the mass of the puck (0.20 kg) to calculate the impulse:
\[ \vec{J} = m \cdot \Delta \vec{v} \]
\[ \vec{J} = 0.20 \, kg \cdot -40 \, m/s \]
\[ \vec{J} = -8.0 \, kg \cdot m/s \]
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