20 Ω 60 Ω 18 Ω 50 Ω 40 Ωξ 60 Ω 75 04 12 Ω 20 Ω 30 Ω

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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a) Calculate the equivalent resistance seen
by the source

b)Calculate the power delivered by the source. 

20 Ω
60 N
18 Q
50 Ω
40 Ω
60 Ω
75 04
12 Q
20 2
30 2
Figuur 3/ Figure 3
Transcribed Image Text:20 Ω 60 N 18 Q 50 Ω 40 Ω 60 Ω 75 04 12 Q 20 2 30 2 Figuur 3/ Figure 3
Expert Solution
Step 1

The power delivered by a current source into a resistive circuit is given by:

Electrical Engineering homework question answer, step 1, image 1

Where,

The current supplied by the current source is “IS”,

The resistance seen by the current source is “Req”.

In the circuit shown in the question, 12Ω resistor is in series with 18Ω resistor and the series combination is in parallel with 60Ω resistor. The combination of 12Ω resistor, 18Ω resistor and 60Ω resistor is in series with 30Ω resistor and the combination of 12Ω resistor, 18Ω resistor, 60Ω resistor and 30Ω resistor is in parallel with 75Ω resistor. The upper 20Ω resistor is parallel with 60Ω resistor.

The resistance of the combination of 12Ω resistor, 18Ω resistor, 60Ω resistor, 30Ω resistor and 75Ω resistor (R1) and resistance of combination of upper 20Ω resistor and 60Ω resistor (R2) are given by:

Electrical Engineering homework question answer, step 1, image 2

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