20 amateur artists are finalists in the San Diego County Fair. If they are all equally qualified, in how many ways can 1st, 2nd and 3rd place winners be chosen? Which strategy would be appropriate for this situation? Select three answers from the list below. 203 20! 3! 20 19 18 Combination 20! 17! 20-19-18 3! 20 20 20 Neither permutation nor combination 20! 17!3! Permutation 00 000 0O 0000

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Problem Statement

20 amateur artists are finalists in the San Diego County Fair. If they are all equally qualified, in how many ways can 1st, 2nd, and 3rd place winners be chosen?

Which strategy would be appropriate for this situation?

Select three answers from the list below:

### Answer Choices

1.  \( 20^3 \)
2.  \( \frac{20!}{3!} \)
3.  \( 20 \times 19 \times 18 \)
4.  Combination: \( \frac{20!}{17! \times 3!} \)
5.  \( \frac{20 \times 19 \times 18}{3!} \)
6.  \( 20 \times 20 \times 20 \)
7.  Neither permutation nor combination
8.  \( \frac{20!}{17!} \)
9.  Permutation: \( \frac{20!}{17!} \)

**Note:**
- Permutations are used where the order matters.
- Combinations are used where the order does not matter.

**Explanation of Concepts:**
1. **Permutations:** The number of ways to arrange a set of items. When selecting winners for 1st, 2nd, and 3rd places, the order does matter, which makes this a permutation problem.
2. **Combinations:** The number of ways to select items from a larger pool where order does not matter.
3. **Factorial Notation (n!):** The product of all positive integers up to \(n\).

### Detailed Explanation of Answer Choices:
1. **\( 20^3 \):** This represents the number of ways to choose 3 winners if repetition was allowed, but it is not relevant for this permutation problem.
2. **\( \frac{20!}{3!} \):** This is not a valid representation for this problem.
3. **\( 20 \times 19 \times 18 \):** This represents the number of ways to choose 1st, 2nd, and 3rd place correctly in order, without repetition.
4. **Combination \( \frac{20!}{17! \times 3!} \):** This would be used if the order of choosing the 3 winners did not matter.
5. **\( \frac{20 \times 19
Transcribed Image Text:### Problem Statement 20 amateur artists are finalists in the San Diego County Fair. If they are all equally qualified, in how many ways can 1st, 2nd, and 3rd place winners be chosen? Which strategy would be appropriate for this situation? Select three answers from the list below: ### Answer Choices 1. \( 20^3 \) 2. \( \frac{20!}{3!} \) 3. \( 20 \times 19 \times 18 \) 4. Combination: \( \frac{20!}{17! \times 3!} \) 5. \( \frac{20 \times 19 \times 18}{3!} \) 6. \( 20 \times 20 \times 20 \) 7. Neither permutation nor combination 8. \( \frac{20!}{17!} \) 9. Permutation: \( \frac{20!}{17!} \) **Note:** - Permutations are used where the order matters. - Combinations are used where the order does not matter. **Explanation of Concepts:** 1. **Permutations:** The number of ways to arrange a set of items. When selecting winners for 1st, 2nd, and 3rd places, the order does matter, which makes this a permutation problem. 2. **Combinations:** The number of ways to select items from a larger pool where order does not matter. 3. **Factorial Notation (n!):** The product of all positive integers up to \(n\). ### Detailed Explanation of Answer Choices: 1. **\( 20^3 \):** This represents the number of ways to choose 3 winners if repetition was allowed, but it is not relevant for this permutation problem. 2. **\( \frac{20!}{3!} \):** This is not a valid representation for this problem. 3. **\( 20 \times 19 \times 18 \):** This represents the number of ways to choose 1st, 2nd, and 3rd place correctly in order, without repetition. 4. **Combination \( \frac{20!}{17! \times 3!} \):** This would be used if the order of choosing the 3 winners did not matter. 5. **\( \frac{20 \times 19
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