20 20 10 10 x (m) 3.0 0.5 1.0 1.5 2.5 - 10 1.0 x (m) 3.0 1.5 2.0 2.5 -10 - 20 - 20 Fx (N) Fx (N) 20 20- 10 10 X (m) 3.0 0.5 10 1.5 2.0 2.5 2.0 X (m) 0.5 1.0 1.5 2.5 3.0 - 10 - 10f -20 - 20 (b) Estimate F (0). -12 Your value is acceptable. N Estimate F(3.0 m). Your value is acceptable. N Estimate the x intercept. 1.71 Your value is acceptable. m Fram.your.graph, find the net work done by the force as the object moves from x = 0 to x = 3 m. (Use your estimates.) Enter a number. Need Help? Read It Watch It

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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### Analysis of Force vs. Displacement Graphs

#### Graphical Representation:

The image displays four graphs, each presenting a plot of force \( F_x \) in Newtons (N) against displacement \( x \) in meters (m). The axes are labeled, with the horizontal axis representing displacement ranging from 0 to 3 meters, and the vertical axis representing force ranging from -20 to 20 Newtons.

**Graph Descriptions:**

1. **Graph (i):**
   - The plot shows a linear decrease in force as displacement increases from 0 to 3 meters. The graph starts at around 15 N at \( x = 0 \) and declines to approximately -10 N at \( x = 3 \).

2. **Graph (ii):**
   - This graph depicts a linear increase in force with displacement. The plot begins at around -10 N at \( x = 0 \) and rises to about 20 N at \( x = 3 \).

3. **Graph (iii):**
   - Similar to graph (i), this graph illustrates a decreasing trend in force, starting from about 15 N at \( x = 0 \) and dropping to approximately -20 N by \( x = 3 \).

4. **Graph (iv):**
   - This plot shows a gentle decrease in force, beginning at around 15 N at \( x = 0 \) and ending near -5 N at \( x = 3 \).

#### Questions and Calculations:

- **(b) Estimate \( F_x(0) \):**
  - Answer: \(-12\) N
  - Interpretation: The initial force at \( x = 0 \) is estimated to be \(-12\) N.

- **Estimate \( F_x(3.0 \, \text{m}) \):**
  - Answer: \(9\) N
  - Interpretation: The force at \( x = 3 \, \text{m} \) is estimated to be \(9\) N.

- **Estimate the x-intercept:**
  - Answer: \(1.71\) m
  - Interpretation: The force becomes zero (crosses the x-axis) at approximately \(1.71\) meters.

- **Net Work Calculation:**
  - Instruction: Use the graph to find the net work done by the force as the object moves from \( x
Transcribed Image Text:### Analysis of Force vs. Displacement Graphs #### Graphical Representation: The image displays four graphs, each presenting a plot of force \( F_x \) in Newtons (N) against displacement \( x \) in meters (m). The axes are labeled, with the horizontal axis representing displacement ranging from 0 to 3 meters, and the vertical axis representing force ranging from -20 to 20 Newtons. **Graph Descriptions:** 1. **Graph (i):** - The plot shows a linear decrease in force as displacement increases from 0 to 3 meters. The graph starts at around 15 N at \( x = 0 \) and declines to approximately -10 N at \( x = 3 \). 2. **Graph (ii):** - This graph depicts a linear increase in force with displacement. The plot begins at around -10 N at \( x = 0 \) and rises to about 20 N at \( x = 3 \). 3. **Graph (iii):** - Similar to graph (i), this graph illustrates a decreasing trend in force, starting from about 15 N at \( x = 0 \) and dropping to approximately -20 N by \( x = 3 \). 4. **Graph (iv):** - This plot shows a gentle decrease in force, beginning at around 15 N at \( x = 0 \) and ending near -5 N at \( x = 3 \). #### Questions and Calculations: - **(b) Estimate \( F_x(0) \):** - Answer: \(-12\) N - Interpretation: The initial force at \( x = 0 \) is estimated to be \(-12\) N. - **Estimate \( F_x(3.0 \, \text{m}) \):** - Answer: \(9\) N - Interpretation: The force at \( x = 3 \, \text{m} \) is estimated to be \(9\) N. - **Estimate the x-intercept:** - Answer: \(1.71\) m - Interpretation: The force becomes zero (crosses the x-axis) at approximately \(1.71\) meters. - **Net Work Calculation:** - Instruction: Use the graph to find the net work done by the force as the object moves from \( x
The problem presents a scenario where the force acting on an object is given by the equation \( F_x = (7x - 12) \, \text{N} \), where \( x \) is the position in meters.

### Task:
(a) Choose the plot that best describes the force versus position \( x \) from \( x = 0 \) to \( x = 3.00 \, \text{m} \).

### Graphs:
1. **Graph (i)**: This graph shows a line with a negative slope, starting at \( F_x = -12 \, \text{N} \) at \( x = 0 \, \text{m} \) and increasing linearly to \( F_x = 0 \, \text{N} \) at \( x \approx 1.71 \, \text{m} \), and to \( F_x = 9 \, \text{N} \) at \( x = 3 \, \text{m} \).

2. **Graph (ii)**: This graph depicts a line with a steep negative slope, starting at \( F_x \approx 10 \, \text{N} \) at \( x = 0 \, \text{m} \) and decreasing linearly to a negative value beyond \( F_x = -20 \, \text{N} \) by \( x = 3.00 \, \text{m} \).

3. **Graph (iii)**: This graph shows a line with a positive slope, starting at \( F_x = -12 \, \text{N} \) at \( x = 0 \, \text{m} \), crossing the x-axis at \( x \approx 1.71 \, \text{m} \), and reaching \( F_x = 9 \, \text{N} \) at \( x = 3.00 \, \text{m} \).

### Solution:
Upon analysis, **Graph (iii)** correctly displays the behavior of the force \( F_x = (7x - 12) \, \text{N} \) over the given range. The force starts at -12 N at \( x = 0 \, \text{m} \) and increases linearly.

### Additional Questions:
(b) Estimate \( F_x(0) \):
Transcribed Image Text:The problem presents a scenario where the force acting on an object is given by the equation \( F_x = (7x - 12) \, \text{N} \), where \( x \) is the position in meters. ### Task: (a) Choose the plot that best describes the force versus position \( x \) from \( x = 0 \) to \( x = 3.00 \, \text{m} \). ### Graphs: 1. **Graph (i)**: This graph shows a line with a negative slope, starting at \( F_x = -12 \, \text{N} \) at \( x = 0 \, \text{m} \) and increasing linearly to \( F_x = 0 \, \text{N} \) at \( x \approx 1.71 \, \text{m} \), and to \( F_x = 9 \, \text{N} \) at \( x = 3 \, \text{m} \). 2. **Graph (ii)**: This graph depicts a line with a steep negative slope, starting at \( F_x \approx 10 \, \text{N} \) at \( x = 0 \, \text{m} \) and decreasing linearly to a negative value beyond \( F_x = -20 \, \text{N} \) by \( x = 3.00 \, \text{m} \). 3. **Graph (iii)**: This graph shows a line with a positive slope, starting at \( F_x = -12 \, \text{N} \) at \( x = 0 \, \text{m} \), crossing the x-axis at \( x \approx 1.71 \, \text{m} \), and reaching \( F_x = 9 \, \text{N} \) at \( x = 3.00 \, \text{m} \). ### Solution: Upon analysis, **Graph (iii)** correctly displays the behavior of the force \( F_x = (7x - 12) \, \text{N} \) over the given range. The force starts at -12 N at \( x = 0 \, \text{m} \) and increases linearly. ### Additional Questions: (b) Estimate \( F_x(0) \):
Expert Solution
Step 1

Work done = area undee F-x graph 

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