20- 16 12 8- 10 15 20 25 30 IT X 1. A baker is creating a birthday cake. Let the region R be bounded by y=20sin and y=0, as pictured above. 30 Both x and y are measured in centimeters. (a) To plan the cake, the baker cuts region R is cut out of a 30-centimeter by 20 centimeter rectangular piece of cardboard, and then discards the remaining cardboard. Find the area of the discarded cardboard. (b) The baker is considering revolving region R about the line x=40 to create a "bundt" style cake. Find the volume of his cake. (c) As a centerpiece of his "bundt" style cake in part (b), the baker would like to fill the "chimney" of the cake (the hole in the center) with meringue and light it on FIRE! Assuming the meringue is level with the top of the cake, find the volume of meringue necessary to construct the baker's centerpiece. 4.

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### Educational Problem Solving in Calculus: Baker's Birthday Cake

**Problem Overview:**
A baker is creating a birthday cake. Let the region \( R \) be bounded by \( y = 20 \sin \left( \frac{\pi x}{30} \right) \) and \( y = 0 \), as depicted below:

#### Graph Description:
- \( x \)-axis ranges from \( 0 \) to \( 30 \) centimeters.
- \( y \)-axis ranges from \( 0 \) to \( 20 \) centimeters.
- The curve \( y = 20 \sin \left( \frac{\pi x}{30} \right) \) forms a sinusoidal shape that peaks at \( y = 20 \) when \( x = 15 \) and crosses the \( x \)-axis at \( x = 0 \) and \( x = 30 \).

**Problem Details:**

1. **Problem Statement:**
   Both \( x \) and \( y \) are measured in centimeters.

   (a) To plan the cake, the baker cuts region \( R \) out of a 30-centimeter by 20-centimeter rectangular piece of cardboard, and then discards the remaining cardboard. Find the area of the discarded cardboard.

   (b) The baker is considering revolving region \( R \) about the line \( x = 40 \) to create a “bundt” style cake. Find the volume of his cake.

   (c) As a centerpiece of his “bundt” style cake in part (b), the baker would like to fill the “chimney” of the cake (the hole in the center) with meringue and light it on FIRE! Assuming the meringue is level with the top of the cake, find the volume of meringue necessary to construct the baker’s centerpiece.

### Step-by-Step Solution:

#### Solution to Part (a):
1. The entire cardboard’s area is \( 30 \text{ cm} \times 20 \text{ cm} = 600 \text{ cm}^2 \).
2. The area of region \( R \):

   \[ \text{Area of } R = \int_{0}^{30} 20 \sin \left( \frac{\pi x}{30} \right) \, dx \]

   Use the integral to find the area under
Transcribed Image Text:### Educational Problem Solving in Calculus: Baker's Birthday Cake **Problem Overview:** A baker is creating a birthday cake. Let the region \( R \) be bounded by \( y = 20 \sin \left( \frac{\pi x}{30} \right) \) and \( y = 0 \), as depicted below: #### Graph Description: - \( x \)-axis ranges from \( 0 \) to \( 30 \) centimeters. - \( y \)-axis ranges from \( 0 \) to \( 20 \) centimeters. - The curve \( y = 20 \sin \left( \frac{\pi x}{30} \right) \) forms a sinusoidal shape that peaks at \( y = 20 \) when \( x = 15 \) and crosses the \( x \)-axis at \( x = 0 \) and \( x = 30 \). **Problem Details:** 1. **Problem Statement:** Both \( x \) and \( y \) are measured in centimeters. (a) To plan the cake, the baker cuts region \( R \) out of a 30-centimeter by 20-centimeter rectangular piece of cardboard, and then discards the remaining cardboard. Find the area of the discarded cardboard. (b) The baker is considering revolving region \( R \) about the line \( x = 40 \) to create a “bundt” style cake. Find the volume of his cake. (c) As a centerpiece of his “bundt” style cake in part (b), the baker would like to fill the “chimney” of the cake (the hole in the center) with meringue and light it on FIRE! Assuming the meringue is level with the top of the cake, find the volume of meringue necessary to construct the baker’s centerpiece. ### Step-by-Step Solution: #### Solution to Part (a): 1. The entire cardboard’s area is \( 30 \text{ cm} \times 20 \text{ cm} = 600 \text{ cm}^2 \). 2. The area of region \( R \): \[ \text{Area of } R = \int_{0}^{30} 20 \sin \left( \frac{\pi x}{30} \right) \, dx \] Use the integral to find the area under
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